The process in beer production that produces carbon dioxide and ethanol is known as
2 answers:
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Answer : The correct option is, (B) 6 mole
Explanation :
Given moles of = 6 moles
Given moles of = 6 moles
First we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the given balanced reaction, we conclude that
As, 1 moles of react with 2 moles of
So, 6 moles of react with
moles of
From this we conclude that, is an excess reagent and
is a limiting reagent because the given moles are less than the required moles and it limits the formation of product.
Thus, the number of moles of NaOH used up in the reaction = Required moles of NaOH - Given moles of NaOH
The number of moles of NaOH used up in the reaction = 12 - 6 = 6 moles
Therefore, the number of moles of NaOH used up in the reaction will be, 60 moles
Answer:
%age Yield = 85.36 %
Solution:
The Balance Chemical Reaction is as follow,
C₆H₁₂O + Acid Catalyst → C₆H₁₀ + Acid Catalyst + H₂O
According to Equation ,
100 g (1 mole) C₆H₁₂O produces = 82 g (1 moles) of C₆H₁₀
So,
4.0 g of C₆H₁₂O will produce = X g of C₆H₁₀
Solving for X,
X = (4.0 g × 82 g) ÷ 100 g
X = 3.28 g of C₆H₁₀ (Theoretical Yield)
As we know,
%age Yield = (Actual Yield ÷ Theoretical Yield) × 100
%age Yield = (2.8 g ÷ 3.28 g) × 100
%age Yield = 85.36 %
