According to the arrhenius concept, if HNO3, were dissolved in water, it would act as?: a. Proton acceptor b. A base c. A source
2 answers:
Answer: d. An acid
Explanation:
According to Arrhenius concept, a base is defined as a substance which donates hydroxide ions when dissolved in water and an acid is defined as a substance which donates hydrogen ions
in water.
A substance that increases the hydrogen ion concentration of a solution is an Arrhenius acid.
Thus as donates a proton , it is considered as an Arrhenius acid.
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Answer:
The first one.
Explanation:
When comparing two fractions with variables like this, it's important to get to the same denominator in order to compare apples with apples and then be able to do not only comparisons but also perform additions/subtractions.
Question is which denominator to use and how to reach it.
In this case, the question and the answer choices do the work for you. The question asks which one is the LEAST common denominator, and the answers show denominators x² and 4x². The smallest of these is x², however, we can't simplify the first fraction to get to the x² denominator, so we'll go for the 4x².
So, the first fraction has already the correct denominator (4x²), we just have to transform the second one.
We multiply it by 1, expressed in a different way. Since we're multiplying by one, we're not affecting the value, just the way it looks.
Let's do it!, to get the denominator to go from x² to 4x², we need to multiply it by 4... so we'll multiply by 4/4 (which is 1, neutral for the multiplication).
And now you have both fractions on the same denominator, without having changed their value, just their looks
Answer:
Explanation:
Molarity is a measure of concentration in moles per liter.
The molarity of the solution is 1.2 M NaNO₃ or 1.2 moles NaNO₃ per liter. There are 0.25 liters of the solution. The moles of solute are unknown, so we can use x.
- molarity= 1.2 mol NaNO₃/L
- liters of solution=0.25 L
- moles of solute =x
We are solving for x, so we must isolate the variable, x. It is being divided by 0.25 liters. The inverse of division is multiplication, so we multiply both sides by 0.25 L.
The units of liters cancel, so we are left with the units moles of sodium nitrate.
There are 0.3 moles of sodium nitrate.