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Ahat [919]
3 years ago
11

Show a correct numerical setup for calculating the average atomic mass of sulfur

Chemistry
1 answer:
luda_lava [24]3 years ago
5 0
Avg. atomic mass=<span>∑i</span><span>(<span>isotopei</span>×<span>abundancei</span><span>)</span></span>
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Convert 512 kilograms to milligrams.<br><br> 0.000512<br> 0.512<br> 512,000<br> 512,000,000
olga55 [171]
The answer is D! 512000000
5 0
3 years ago
Read 2 more answers
Will mark brainliest!
777dan777 [17]
People use data tables and graphs in many financial careers and when looking at the statistics for something as simple as what they saw on the news, etc. When scientists use them, they’re both using them to see the numbers and the facts. They’re both able to use graphs and data tables to help them. They are different though because scientists use them for science related things like how much a tree grew in a year while everyday people use them to see the average amount of drop outs per year or something along those lines.

Data tables and graphs are very vital to a scientists job. They help them easily collect and organize information to where anyone can read it. It may not be absolutely necessary, but it’s something every scientist uses.

Any scientist doing any sort of research would use them. Whether they’re a biologist, geologist or whatever, they all use graphs and data tables to help them organize their research.
4 0
3 years ago
A less-intense wave will have fewer _____ than a more-intense wave.
Shalnov [3]
A less intense wave will have fewer OSCILLATING AMPLITUDE than a more intense wave.
The intensity of a wave is the power transferred per unit area, where the area is measured on the plane perpendicular to the direction of propagation of the energy. Intense sounds are characterized by the particles of the medium vibrating back and forth with large amplitude.<span />
3 0
3 years ago
Read 2 more answers
600.0 mL of air is at 20.0 c what is the volume at 60.0
pogonyaev

682mL

Explanation:

Given parameters:

Initial volume of air = 600mL

Initial temperature = 20°C

Final temperature = 60°C

Unknown:

Final volume = ?

Solution:

To solve this problem, we apply Charles's law';

Charles's law states that "at constant pressure, the volume of a given mass of gas is directly proportional to its temperature. "

Mathematically;

   \frac{V_{1} }{T_{1} }  = \frac{V_{2} }{T_{2} }

V₁ is the initial volume  of air

T₁ is the initial temperature  of air

V₂ is the final volume  of air

T₂ is the final temperature of air

To proceed in solving this problem, we need to convert the given temperature to Kelvin;

T K = 273 + T°C

T₁  = 273 + 20 = 293K

T₂ = 273 + 60 = 333K

now input the parameters;

V_{2}  = \frac{V_{1} }{T_{1} }  x T_{2}  = \frac{600}{293 }  x 333

 V₂ = 682mL

learn more:

Gas laws brainly.com/question/2438000

#learnwithBrainly

 

8 0
3 years ago
Match each substance with the correct designation for the equation HSO3- + CH3NH2 &lt;=&gt; SO32- + CH3NH3+ HSO3- CH3NH2 SO32- C
Zanzabum

Answer:

HSO_3^-: conjugate acid of SO_3^{2-}

CH_3NH_2 : conjugate base of CH_3NH_3^+

SO_3^{2-} : conjugate base of HSO_3^-

CH_3NH_3^+ : conjugate acid of CH_3NH_2

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

HSO_3^-+CH_3NH_2\rightleftharpoons SO_3^{2-}+CH_3NH_3^+

Here in forward reaction CH_3NH_2 is accepting a proton, thus it is considered as a base and after accepting a proton, it forms CH_3NH_3^+ which is a conjugate acid.

And HSO_3^-  is losing a proton, thus it is considered as an acid and after loosing a proton, it forms SO_3^{2-} which is a conjugate base.

Similarly in the backward reaction, CH_3NH_3^+ is loosing a proton, thus it is considered as a acid and after loosing a proton, it forms CH_3NH_2 which is a conjugate base.

And SO_3^{2-}  is accepting a proton, thus it is considered as a base and after accepting a proton, it forms HSO_3^{-} which is a conjugate acid.

4 0
3 years ago
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