Question

The vector v=(7,1) lies entirely in quadrant 1. Give possible coordinates for the initial point and terminal point of the vector. Show your work and explain your reasoning

Answer 1

Answer:

A possible initial point is (1,4) and a possible terminal point is (8,5)

Step-by-step explanation:

The given vector is $\vec{v}=(7,1)$.

We can rewrite this vector as:

$\vec{v}=\binom{7}{1}$

The x-components is 7 and the y-component is 1.

We can choose initial point (a,b) and terminal point (c,d) in the first quadrant such that $c-a=7$  and $d-b=1$

If a=1, and b= 4, then:

$c-1=7$  and $d-4=1$

This implies that:

$c=7+1=8$  and $d=1+4=5$

Therefore a possible initial point is (1,4) and a possible terminal point is (8,5)