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3 years ago

8

What is7/9 as a percentage

2 answers:

Kobotan [32]3 years ago

8 0

I think it is 77% or 77.7`% ,but tell me if I'm wrong

valina [46]3 years ago

8 0

<span>To change a fraction to percent form, divide its numerator by its denominator. Then, take the result and multiply by 100. </span><span>
</span><span>So,</span><span>7/9</span><span>=0.7777777778*100</span><span>=77.777778%</span>

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Olegator [25]

0.084 is the answer because 0.84 divided by 10 is 0.084

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3 years ago

How to find the area of a equilateral triangle that has a perimeter of 21?

Romashka-Z-Leto [24]

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3 years ago

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mars1129 [50]

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Step-by-step explanation:

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<h2><u>Refer</u><u> this</u><u> attachment</u></h2>

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3 years ago

In Vancouver, British Columbia, the probability of rain during a winter day is 0.42, for a spring day is 0.23, for a summer day

nadezda [96]

Answer:

31.82% probability that this day would be a winter day

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening

In this question:

Event A: Rain

Event B: Winter day

Probability of rain:

0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).

So

$P(A) = 0.42*0.25 + 0.23*0.25 + 0.16*0.25 + 0.51*0.25 = 0.33$

Intersection:

Rain on a winter day, which is 0.42 of 0.25. So

$P(A \cap B) = 0.42*0.25 = 0.105$

If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?

$P(B|A) = \frac{0.105}{0.33} = 0.3182$

31.82% probability that this day would be a winter day

6 0

3 years ago