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vesna_86 [32]
3 years ago
7

Which of the following shows the true solution to the logarithmic equation 3 log Subscript 2 Baseline (2 x) = 3

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
7 0

Answer:

x = 1

Step-by-step explanation:

We have to solve the given logarithmic equation of variable x.

The equation is 3\log _{2} (2x) = 3

⇒ \log_{2} (2x)^{3} = 3  

{Since, we know the logarithmic property, a \log b = \log b^{a}}

⇒ \log_{2} (2x)^{3} = 3\log_{2}2 = \log_{2} 2^{3}

{Since we know that \log_{a} a = 1}

Now cancelling log from both sides we get,  

(2x)^{3} = 2^{3}

⇒ x^{3} = 1

⇒ x = 1 (Answer)

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The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth
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As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

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\twoheadrightarrow \quad\sf{ Length =2(Width)-5}

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\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\

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\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\

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\\ \twoheadrightarrow \quad\sf{60= 6b} \\

\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\

\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\

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\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}

\twoheadrightarrow \quad\sf{ \ell=20-5\; m}

\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\

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