Consider the balanced equation shown and identify the statement that is not true. Na2SO4 (aq) + BaCl2 (aq) → 2 NaCl (aq) + BaSO4
1 answer:
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Here we go ~
1 mole of has 6.022 × 10²³ molecules of the given compound.
So, 0.78 mole of will have ~
<u>Answer:</u> The molality of solution is 0.740 m.
<u>Explanation:</u>
To calculate the mass of solvent (water), we use the equation:
Volume of water = 750 mL
Density of water = 1 g/mL
Putting values in above equation, we get:
To calculate the molality of solution, we use the equation:
Where,
= Given mass of solute
= 100.0 g
= Molar mass of solute
= 180 g/mol
= Mass of solvent (water) = 750 g
Putting values in above equation, we get:
Hence, the molality of solution is 0.740 m.