Question

If 16.5g of c6h14o2 are reacted vwith .499 mol of o2. How many moles of co2 should be produced

Answer 1

Answer:

moles of carbon dioxide produced are 410.9 mol.

Explanation:

Given data:

Mass of C₆H₁₄O₂ = 16.5 g

Moles of O₂ = 499 mol

Moles of CO₂ = ?

First of all we will write the balance chemical equation.

2C₆H₁₄O₂  +  17O₂  →   14CO₂  +  12H₂O

moles of C₆H₁₄O₂  = mass × molar mass

moles of C₆H₁₄O₂ =  16.5 g × 118 g/mol

moles of C₆H₁₄O₂ = 1947 mol

Now we compare the moles of CO₂ with moles of O₂ and C₆H₁₄O₂ from balance chemical equation.

                 O₂      :     CO₂

                 17       :      14

                499     :      14/17× 499 = 410.9 moles

          C₆H₁₄O₂   :   CO₂

                    2    :      14

                 1947 :     14/2× 1947 =  13629 moles

Oxygen will be limiting reactant so moles of carbon dioxide produced are 410.9 mol.

Answer 2

Answer:

1.96 mole

Explanation:

Thinking process:

First, we have to write a balanced chemical equation:

$C_{6}H_{14}O_{2} + 17O_{2} = 14CO_{2} + 12H_{2}O$

the mass of C6H14O2  = 16.5

the molar mass of C6H14O2 = 118.0

the number of moles of C6H14O2 = $\frac{16.5}{118} \\ =0.140 mole$

the number of moles produced = 14 × number of moles of C6H14O2

                                                     = 14 × 0.140 mole

                                                     = 1.96 mole