The first step is to make a balanced chemical equation.
2AgNO3 + CaCl2 ---> 2AgCl + Ca(NO3)2
Molecular Weights:
CaCl2 = 110.98 g/mol
AgNO3 =170.01
AgCl: 143.45 g/mol
Volume:
CaCl2: 30.0mL=0.03L
AgNO3: 15.0mL=0.015 L
Solving for the limiting reactant one needs to get the mols CaCl2 and mols AgNO3:
CaCl2: 0.150M(mol/L) * 0.03L = 0.0045 moles
AgNO3: 0.100M*0.015L = 0.0015 moles
Since the stoichiometric ratio of AgNO3 to CaCl2 is 2:1
0.0015 mols AgNO3 *(1 mol CaCl2/ 2 mols AgNO3) = 0.00075 mols CaCl2
Since the answer is lesser than CaCl2 then the limiting reactant is AgNO3.
To get the mass of AgCl one will do a stoichiometric calculation with respect to the limiting reactant, AgNO3.
0.0015 moles AgNO3 *
Iron and steel are magnetic in nature. So you can use a magnet to separate them
4.5 × 10⁻⁵ L of NH₃ are needed per liter of flue gas at 1.00 atm.
<h3>What is Balanced Chemical Equation ?</h3>
The equation during which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation is called balanced chemical equation.
The given balanced chemical equation is
4NH₃(g) + 4NO(g) + O₂(g) → 4N₂(g) + 6H₂O(g)
<h3>How to find mole fraction ?</h3>
To find mole fraction use this expression
P.P = M.F × T.P
where,
P.P = Partial Pressure
M.F = Mole Fraction
T.P = Total pressure
Here,
Given flue gas total pressure (T.P) is 1.00 atm
Given NO Partial Pressure (P.P) = 4.5 × 10⁻⁵
Now putting the values we get
P.P = M.F × T.P
4.5 × 10⁻⁵ atm = 1.00 atm × M.F
M.F = 4.5 × 10⁻⁵ L
Thus from the above conclusion we can say that 4.5 × 10⁻⁵ L of NH₃ are needed per liter of flue gas at 1.00 atm.
Learn more about Mole Fraction here: brainly.com/question/1601411
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Answer:
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Explanation:
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