6x+10=58
6x=48
/6. /6.
x=8
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Answer:
Hope it may help u
Step-by-step explanation:
The sum of two numbers is 44 and their difference is 14. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.
The sum of x and y is 44. In other words, x plus y equals 44 and can be written as equation A:
x + y = 44
The difference between x and y is 14. In other words, x minus y equals 14 and can be written as equation B:
x - y = 14
Now solve equation B for x to get the revised equation B:
x - y = 14
x = 14 + y
Then substitute x in equation A from the revised equation B and then solve for y:
x + y = 44
14 + y + y = 44
14 + 2y = 44
2y = 30
y = 15
Now we know y is 15. Which means that we can substitute y for 15 in equation A and solve for x:
x + y = 44
x + 15 = 44
X = 29
Summary: The sum of two numbers is 44 and their difference is 14. What are the two numbers? Answer: 29 and 15 as proven here:
Sum: 29 + 15 = 44
Difference: 29 - 15 = 14
Answer: b) ΔADC ≡ ΔBCD by SAS
<u>Step-by-step explanation:</u>
Step 1: AD = BC SIDES are congruent
Step 2: ∠ADC ≡ ∠BCD ANGLES are congruent
Step 3: DC = DC SIDES are congruent
The proof is using Side-Angle-Side (SAS)
Look at the angles in step 2. These are the triangles you are proving congruency for: ΔADC ≡ ΔBCD