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Annette [7]
3 years ago
10

What is 20 times 3/5 in simplest form?

Mathematics
2 answers:
eduard3 years ago
7 0
20 x 3/5 would equal 12
stealth61 [152]3 years ago
5 0
You can write it like this:
20/1 * 3/5

And then you can multiply to get this:
60/5

And then you can determine how many 5 go in 60 to figure out the exact number which is 12!

I hope that helps! Feel free to let me know if you have any questions! :3

- mathwizzard3
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Rachel finished 3/4 of the race in 6 hours. How long was the entire race?
s344n2d4d5 [400]
6=.75x
x= 8 hours for the whole race

5 0
3 years ago
Read 2 more answers
The number of events is 29​, the number of trials is 298​, the claimed population proportion is​ 0.10, and the significance leve
Nina [5.8K]

Answer:

z=\frac{0.0973 -0.1}{\sqrt{\frac{0.1(1-0.1)}{298}}}=-0.155  

p_v =2*P(Z  

And we can use excel to find the p value like this: "=2*NORM.DIST(-0.155;0;1;TRUE)"

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly different from 0.1 .  

Step-by-step explanation:

1) Data given and notation

n=298 represent the random sample taken

X=29 represent the events claimed

\hat p=\frac{29}{298}=0.0973 estimated proportion

p_o=0.1 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is 0.1 or no.:  

Null hypothesis:p=0.1  

Alternative hypothesis:p \neq 0.1  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.0973 -0.1}{\sqrt{\frac{0.1(1-0.1)}{298}}}=-0.155  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z  

And we can use excel to find the p value like this: "=2*NORM.DIST(-0.155;0;1;TRUE)"

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly different from 0.1 .  

We can do the test also in R with the following code:

> prop.test(29,298,p=0.1,alternative = c("two.sided"),conf.level = 1-0.05,correct = FALSE)

7 0
2 years ago
The sum of three consecutive integers is 168. What are the integers
Tema [17]

Answer:

3X + 3 = 168

3X + 3 - 3 = 168 - 3

3X = 165

3X/3 = 165/3

X = 55

Step-by-step explanation:

We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 168. Therefore, you can write the equation as follows: (X) + (X + 1) + (X + 2) = 168

3 0
2 years ago
Can i solve an addition to different variables
Yuliya22 [10]

Answer:

no unless the variables are known

Step-by-step explanation:

8 0
3 years ago
An exponential growth function has an asymptote of y = –3. Which might have occurred in the original function to permit the rang
Blababa [14]

The right choice is: A <em>whole</em> number constant could have been <em>subtracted</em> from the <em>exponential</em> expression.

Let be an <em>exponential</em> function of the form y = A\cdot e^{B\cdot x}, where A and B are <em>real</em> numbers. A <em>horizontal</em> asymptote exists when e^{B\cdot x} \to 0, which occurs for B\cdot x \to - \infty.

For this function, the <em>horizontal</em> asymptote is represented by y = 0 and to change the value of the asymptote we must add the <em>parent</em> function by another <em>real</em> number (C), that is to say:

y = A\cdot e^{B\cdot x} + C (1)

In this case, we must use C = -3 to obtain an horizontal asymptote of -3. Thus, the right choice is: A <em>whole</em> number constant could have been <em>subtracted</em> from the <em>exponential</em> expression.

To learn more on asymptotes, we kindly invite to check this verified question: brainly.com/question/8493280

3 0
2 years ago
Read 2 more answers
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