1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lina20 [59]
3 years ago
5

Phil can afford $200 a month for 5 years for a car loan. if the interest rate is 7.5 percent, how much can he afford to borrow t

o purchase a car?

Mathematics
2 answers:
madreJ [45]3 years ago
6 0
200 per month for 5 years = 12,000
Phil can (at most) pay 12,000 for the car loan.
That would be the payment total.
So, how do we solve for the PRINCIPAL?
Looking at the attached formula, we see the
principal = Total - Total * ((1 +r)^-n) / r * n
where n = # of payments = 5 year * 12 months = 60 and
rate / 1.200 = 7.5/1,200 = .00625
 
principal = [12,000 - 12,000 * (1.00625)^-60] / .375
principal = [12,000 - 12,000 * <span> <span> <span> 0.6880918239 </span> </span> </span> ] / .375
principal = [12,000 - <span> <span> <span> 8,257.1018863488] / .375
</span></span></span>principal = <span> <span> <span> 3,742.</span></span></span>90 / .375
principal = 9,981.06

Source:
http://www.1728.org/loanfrm4.htm


Lesechka [4]3 years ago
5 0

Answer:

$24,952.65

Step-by-step explanation:

Phil can afford $200 a month for 5 years for a car loan. if the interest rate is 7.5 percent.

Loan formula:

E=\dfrac{P\cdot \frac{r}{n}}{1-(1+\frac{r}{n})^{-n\time t}}

where,

P is loan amount, P=?

E is monthly payment, E=$500

n is payment mode, n=12

t is time, t=5 years

r is rate of interest, r = 0.075

Substitute the value into formula and solve for P

500=\dfrac{P\cdot \frac{0.075}{12}}{1-(1+\frac{0.075}{12})^{-12\time 5}}

P=\frac{500\cdot\left(1-\left(1+\frac{0.075}{12}\right)^{-60}\right)}{\frac{0.075}{12}}

P=24952.65

Hence, Phil can borrow to purchase a car be $24,952.65

You might be interested in
sets of linear systems wherein there is one Consistent &amp; Dependent, Consistent &amp; Independent, and one Inconsistent.
Mamont248 [21]

Answer:

What is the difference between entering a formula and entering data ??

3 0
2 years ago
3x^2+20x+12<br> pls show work ;-;
RoseWind [281]

Answer:

3 {x}^{2}  + 20x + 12 \\ 3 {x}^{2}  + 18x + 2x + 12 \\ 3x(x + 6) + 2(x + 6) \\( 3x + 2)(x + 6)

5 0
2 years ago
The yearly attendance at a local movie theater is 68,000 and grows continuously at a rate of 3.5% each year what is the approxim
asambeis [7]

3.5 \times 8 - 68000
the answer is 67972
7 0
3 years ago
Read 2 more answers
Find the smallest value of n such that the LCM of n and 15 is 45
krek1111 [17]

Answer:45


Step-by-step explanation:

9 and 15 both go into 45, and 45 is the LCM of those numbers.

6 0
3 years ago
Read 2 more answers
Add.<br> (8a + 2b - 9) + (-11a - 5b + 4)
Valentin [98]

Answer:

(-3a -3b -5)

Step-by-step explanation:

So you have to add numbers with same valuables

  1. 8a+(-11a) Answer: -3a
  2. 2b+(-5b) Answer: -3b
  3. -9+4 Answer: -5

4 0
3 years ago
Other questions:
  • Mika can eat 21 hot dogs in 6 minutes. She wants to know how many minutes ( m ) it would take her to eat 35 hot dogs if she can
    10·1 answer
  • 3/7 of the people living in the apartment building are men. 5/8 of the remaining are women. The rest are children. A total of 27
    13·1 answer
  • Which of the following best describes y with respect to x in the equation y=3x-2?​
    5·1 answer
  • Why can a problem with extra information be difficult to solve?
    9·2 answers
  • Find the HCF of 168 and 196.
    6·2 answers
  • Can someone help me?
    9·1 answer
  • A circle has a circumference of 28.36 units what is the diameter of the circle
    12·2 answers
  • Z – 9 = 27<br> a. 3<br> b. 16<br> c. 18<br> d. 36
    10·2 answers
  • The Income-tax for the state of Kalamazoo is as follows:
    9·1 answer
  • 0,2,2,4,?,10,16,26.... which number replaces the question mark in the number pattern shown
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!