Common Pythagorean triples include (3, 4, 5) (5, 12, 13) (7, 24, 25) (9, 40, 41) The only Pythagorean triple that is an arithmetic sequence is (3, 4, 5), so any arithmetic sequence that is a Pythagorean triple must be a multiple of that, such as (9, 12, 15) or (15, 20, 25).
The arithmetic sequences of selections B and D are unrelated to the (3, 4, 5) triple, so cannot be Pythagorean triples. For selection A, we know that 9² + 11² = 81 + 121 = 202 > 14², so that is not a right triangle.
Since E is the midpoint, AE and EB are equal. We can write this as such,
4x+6=10x-12 if we solve from here we get 6x=18. Simplify to get x=3. sub in three for x in the AE equation, 4(3)+6 and solve. You'd get 18 as your answer. Double that to get the solution since AE= 1/2AB. 18*2= 36
The concept that can be used in order to answer this item is that of man-days. The total number of man-days required to do the job should always be constant.
This can be illustrated by the givens above. Scenario 1: N1 = (4 employees)(4 days) = 16 man-days