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Anna11 [10]
3 years ago
6

The coefficient of y in 2x – 3y is ------------------- (3, -3, 2)

Mathematics
1 answer:
Maslowich3 years ago
7 0

Answer:

coefficient of y is -3.

Step-by-step explanation:

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Jerome works as a waiter. He earns $80 each weekend plus 15% in tips based on the cost of the meals served.
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Answer:

He gets paid $80 each weekend, and a 15% with tips.

you would need to figure out the tips, by taking the $725 and timesing it by .15 for the percent.

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Step-by-step explanation:

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3 years ago
Mrs. Chip bought 2 sheets and a blanket and paid $41. Mrs. Dale bought a sheet and 4 blankets and paid $80.
Katyanochek1 [597]

Answer:

  • Sheet = $12
  • Blanket = $17

Step-by-step explanation:

<u>Let the cost of a sheet be s and cost of a blanket be b</u>

  • 2s + b = 41
  • s + 4b = 80

<u>From the first equation we get:</u>

  • b = 41 - 2s

<u>Substitute in the second equation</u>

  • s + 4*(41 - 2s) = 80
  • s + 164 - 8s =  80
  • 7s = 84
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<u>Then</u>

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A rectangle has a length of x inches and a width of y inches
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3 years ago
I need this answered Fast if possible. A car is traveling on a small highway and is either going 55 miles per hour or 35 miles
Alex787 [66]

a. It spends about 2.045 hours going 55 miles per hour

b. It spends 1 hour going 35 miles per hour

c. The trip would take about 3.64 hours

Step-by-step explanation:

A car is traveling on a small highway and is either going 55 miles per hour or 35 miles  per hour, depending on the speed limits, until it reaches its destination 200 miles  away

  • x represents the amount of time in hours that the car is going 55 miles per  hour
  • y represents the amount of time in hours that the car is going 35 miles per hour
  • The equation  that describing the relationship is 55x + 35y = 200

We need to find:

a. How long does it  spend going 55 miles per hour, if the car spends 2.5 hours going 35 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 2.5 hours going 35 miles per hour on the trip

∵ y represents the amount of time that the car going 35 mi./h

∴ y = 2.5

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(2.5) = 200

∴ 55x + 87.5 = 200

- Subtract 87.5 from both sides

∴ 55x = 112.5

- Divide both sides by 55

∴ x = 2.045 hours

It spends about 2.045 hours going 55 miles per hour

b.how long does it  spend going 35 miles per hour, if the car spends 3 hours going 55 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 3 hours going 55 miles per hour on the trip

∵ x represents the amount of time that the car going 55 mi./h

∴ x = 3

- Substitute the value of y in the equation to find the value of x

∴ 55(3) + 35y = 200

∴ 165 + 35y = 200

- Subtract 165 from both sides

∴ 35y = 35

- Divide both sides by 35

∴ y = 1 hour

It spends 1 hour going 35 miles per hour

c. How long would the trip take, if the car spends no time going 35 miles per hour

∵ 55x + 35y = 200

∵ The car spends no time going 35 miles per hour

∴ y = 0

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(0) = 200

∴ 55x  = 200

- Divide both sides by 55

∴ x = 3.63 hours

The trip would take about 3.64 hours

Learn more:

You can learn more about the equations in brainly.com/question/4097107

#LearnwithBrainly

5 0
3 years ago
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