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3 years ago

What is the value of the expression shown below 10+(2x3)^2 divided by 4x (1/2)^3

Mathematics

1 answer:

stira [4]3 years ago

7 0

Answer:

10 + (2 x 3)^2 / 4 x (1/2) ^3

First do the parentheses

2 x 3 = 6

1 / 2 = 0.5

We are left with

10 + 6^2 /4 x 0.5^3

Do exponents

6 x 6 = 36

0.5 x 0.5 x 0.5 = 0.125

10 + 36 / 4 x 0.125

Divide by 4 and multiply by 0.125

36 / 4 = 9

9 x 0.125 = 1.125

We are left with

10 + 1.125 = 11.125

The answer is 11.125

Step-by-step explanation:

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Consider these functions:<br> f(x) = x + 1<br> g(x)= 2/x

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Answer:

its letter A.

$\frac{2}{x + 1}$

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3 years ago

What 54/100 in simplest form

DanielleElmas [232]

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27/50

Step-by-step explanation:

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Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S.

sweet-ann [11.9K]

Answer:

2.794

Step-by-step explanation:

Recall that if G(x,y) is a parametrization of the surface S and F and G are smooth enough then

$\bf \displaystyle\iint_{S}FdS=\displaystyle\iint_{R}F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})dxdy$

F can be written as

F(x,y,z) = (xy, yz, zx)

and S has a straightforward parametrization as

$\bf G(x,y) = (x, y, 3-x^2-y^2)$

with 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\frac{\partial G}{\partial x}= (1,0,-2x)\\\\\displaystyle\frac{\partial G}{\partial y}= (0,1,-2y)\\\\\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y}=(2x,2y,1)$

we also have

$\bf F(G(x,y))=F(x, y, 3-x^2-y^2)=(xy,y(3-x^2-y^2),x(3-x^2-y^2))=\\\\=(xy,3y-x^2y-y^3,3x-x^3-xy^2)$

and so

$\bf F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})=(xy,3y-x^2y-y^3,3x-x^3-xy^2)\cdot(2x,2y,1)=\\\\=2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2$

we just have then to compute a double integral of a polynomial on the unit square 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\int_{0}^{1}\displaystyle\int_{0}^{1}(2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2)dxdy=\\\\=2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}ydy+6\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^4dy+\\\\+3\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}x^3dx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}y^2dy$

=1/3+2-2/9-2/5+3/2-1/4-1/6 = 2.794

5 0

3 years ago

(5ab-9a-4) - (-4ab + 5)

qaws [65]

Answer:

9ab - 9a +1

Step-by-step explanation:

first, we can distribute the negative sign to the second set of parentheses.

-(-4ab + 5) becomes + 4ab - 5

now let's put the values in (5ab-9a-4) side by side with the corresponding values in + 4ab - 5

5ab + 4ab - 9a - 4 - 5

= 9ab - 9a - 9, because 5ab + 4ab = 9ab, -9a is alone, and -4 - 5 = -9.

8 0

3 years ago

Free points hope this helps you a little!<br> luv you!

nikdorinn [45]

Answer:

thx chief

Step-by-step explanation:

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