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svp [43]
3 years ago
12

How do I simplify this?

Mathematics
1 answer:
nikitadnepr [17]3 years ago
5 0
\bf \cfrac{x^3+6x^2+3x+18}{3x^2+9}\div \cfrac{x+6}{x+1}\\\\
-----------------------------\\\\
(x^3+6x^2)+(3x+18)\implies x^2\underline{(x+6)}+3\underline{(x+6)}\leftarrow \textit{common \underline{factor}}
\\\\\\
(x+6)(x^2+3)\\\\
-----------------------------\\\\
thus\\\\\\
\cfrac{(x+6)(x^2+3)}{3(x^2+3)}\div \cfrac{x+6}{x+1}\implies \cfrac{(x+6)(x^2+3)}{3(x^2+3)}\cdot  \cfrac{x+1}{x+6}
\\\\\\
\cfrac{x+1}{3}
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4 0
3 years ago
How would I do this problem?
kenny6666 [7]

If it's a geometric sequence then:

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a_4=a_3r\to a_4=20.25\cdot0.75=15.1875\\\\a_5=a_4r\to a_5=15.1875\cdot0.75=11.390625

Answer:

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7 0
3 years ago
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tiny-mole [99]
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The second way is to FOIL them out.  When you check B you get k^{2} -5kf+10kf- 50f^{2} combine your like terms and you have your original expression of k^{2} +5kf-50 f^{2}

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7 0
2 years ago
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malfutka [58]
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</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
4 0
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