Answer:
the last one
Step-by-step explanation:
Answer:
No, a triangle cannot be constructed with sides of 2 in., 3 in., and 6 in.
For three line segments to be able to form any triangle you must be able to take any two sides, add their length and this sum be greater than the remaining side.
2
in.
+
3
in.
=
5
in.
5
in.
<
6
in.
For a triangle with sides 3 in., 4 in. and 5 in. which can form a triangle:
3 + 4 = 7 which is greater than 5
3 + 5 = 8 which is greater than 4
4 + 5 = 9 which is greater than 3
Step-by-step explanation:
As x increases without bound, f(x) also increases without bound
think the answer is
x=6+sqrt0/2 x=6-sqrt0/2 both equaling into 3.
But I might be wrong.
Answer:
10(5v-6)
Step-by-step explanation:
