Question

Two triangles are similar.The the smaller triangle has side 10,20 and 15 units the larger triangles longest side is 52 units.What is the perimeter of the largest triangle?

Answer 1

Answer: The perimeter of the largest triangle = 117 units.

Step-by-step explanation:

Sides of smaller triangle = 10,20 and 15 units

Longest side = 20 units

Longest side of larger triangle = 52 units

Sides of two similar triangles are proportional.

Let k be proportionality constant.

$k=\dfrac{\text{Length in larger triangle}}{\text{Length in smaller triangle}}$

$k=\dfrac{52}{20}\\\\\Rightarrow\ k=\dfrac{13}{5}$

Length of other two sides,

$10\times\dfrac{13}{5}, 15\times\dfrac{13}{5}\ i.e.\ 26\text{ units}, 39\text{ units.}$

So sides of larger triangle = 52 units, 26 units , 39 units

Perimeter of largest triangle = 52 +26+39 = 117 units

Hence, the perimeter of the largest triangle = 117 units.