Question

Will give brainiest algebra 2

Answer 1

The sum of squares of numbers is: 13

Step-by-step explanation:

Let x and y be two numbers

Then,

Difference of the squares of the numbers will be:

$x^2-y^2$

Product will be:

$xy$

Given identity is:

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Given values are:

Difference of the squares of the numbers=$x^2-y^2=5$

Product of numbers = xy = 6

Putting the values in the identity

$(x^2+y^2)^2=(5)^2+[2(6)]^2\\=25+(12)^2\\=25+144\\=169$

As we have to only find x^2+y^2

Taking square root on both sides

$\sqrt{(x^2+y^2)^2}=\sqrt{169}\\x^2+y^2=13$

The sum of squares of numbers is: 13

Keywords: Identities

Learn more about identities at:

• brainly.com/question/8902155
• brainly.com/question/8955867

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