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saveliy_v [14]
3 years ago
13

What is this answer?

Mathematics
1 answer:
TiliK225 [7]3 years ago
7 0

Answer:

Your answer is

B

Mark my answer as brainlist . I need that urgently . Folow me for more answer.

Step-by-step explanation:

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Yes or no ? i need help
coldgirl [10]

Answer:

Yes it is linear

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Janice has three times as many dimes as nickels. If the total value of the money is $9.10, how many of each types of coin does s
ICE Princess25 [194]
X= number of nickels
3x= number of dimes

Each nickel is $0.05 and each dime is $0.10. Multiply each coins monetary value by the quantity of each. Add them equal to the total $9.10.

(0.05 * x) + (0.10 * 3x)= 9.10
multiply inside parentheses

0.05x + 0.3x= 9.10
add

0.35x= 9.10
divide both sides by 0.35x

x= 26 nickels


DIMES
3x= 3(26)= 78 dimes

CHECK:
(26 nickels * 0.05) + (78 dimes * 0.10)= 9.10
$1.30 + $7.80= $9.10
$9.10= $9.10


ANSWER: There are 26 nickels and 78 dimes.

Hope this helps! :)
3 0
4 years ago
In a casino in Blackpool there are two slot machines (machine 1 and machine 2): one that pays out 10 % of the time, and one that
otez555 [7]

Answer:

Given that;

a)

2 machines, 1 and 2

Machine 1

pays 10% of times when the machine is generous

So the probability that the machine 1 pays given that its generous is

P (Pays/machine 1 is generous) = 10% = 0.10

Machine 2  

pays 20% of times when its generous

i.e the probability that the machine pays given that its generous is;

P (Pays / machine 2 is generous) = 20% = 0.20

Also we assume there is equal chance of being generous

i.e

P(machine 1 is generous) = P(machine 2 is generous ) = 0.5  

b)

this is to help obtain the probability that machine 1 is generous given that the player loose in the first bet,

i.e P(machine 1 is generous / lost)  

c)

Since, the probability that the machine is generous is 0.5,

it can be said that there is 50% chance that machine 1 is generous when the player loses the first bet

d)

therefore The required probability is calculated as;

P(machine 1 is generous/lost) = p(machine 1 is generous ∩ lost) / p (lost)

= [p(lost/machine 1 is generous) × p(machine 1 is generous)] / [{(1-p(pays/machine 1 is generous)) × p(machine 1 is generous)} + {((1-p(pays/machine 2 is generous)) × p(machine 2 is generous)}]

= [(1 - p(pays/machine 1 is hereous)) × p(machine 1 is generous)] × [(( 1- 0.10) × 0.5) + ((1 - 0.20) × 0.5)]

= ( 1- 0.10) × 0.5) / 0.85

= 0.5294

so  the probability that the player loses the first bet given that the machine is generous is 0.5294

e)

Since the gotten probability that the player loses the first bet given that machine 1 is generous is close to 0.50 then it can be said that the probability is consistent with the expectations.

5 0
3 years ago
How many times does 7 go into 357
zysi [14]
7 goes into 357  51 times. First you take 35 and see how many times 7 goes into that and that is 5 than you take 7 and see how many times 7 goes into that and that is 1 time so that you take your to answers and you get 51 as the final answer.
7 0
3 years ago
Read 2 more answers
I don't know this question.
tino4ka555 [31]

Answer:

It would be a

Step-by-step explanation:

Because 56 divided by 7 = 8

and you should know what divided means when your doing it

8 0
3 years ago
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