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MakcuM [25]
3 years ago
5

Which is bigger, one-fifth of 35 or two-sixths of 24?

Mathematics
1 answer:
GREYUIT [131]3 years ago
5 0

Answer:

two-sixths of 24

Step-by-step explanation:

7<8

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The Answer to This Question
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Recall the Trigonometric Ratio below:

\tt{ \large{sin \theta =  \frac{opposite}{hypotenuse} } }\\   \tt{\large{cos \theta =  \frac{adjacent}{hypotenuse} }} \\    \tt{ \large{tan \theta =  \frac{opposite}{adjacent} }}

For csc, sec and cot - they are reciprocal of sin,cos and tan.

\tt{ \large{csc  \theta =  \frac{1}{sin \theta} } }\\  \tt{ \large{sec \theta =  \frac{1}{cos \theta} }} \\  \tt{ \large{cot \theta =  \frac{1}{tan \theta} }}

What we know now is our hypotenuse, adjacent and opposite length.

  • hypotenuse = 15
  • opposite = 12
  • adjacent = 9

Therefore,

\large{sin \theta =  \frac{12}{15}  \longrightarrow  \frac{4}{5} } \\ \large{cos \theta =  \frac{9}{15}   \longrightarrow  \frac{3}{5} } \\  \large{ tan \theta =  \frac{12}{9}  \longrightarrow  \frac{4}{3} }As for the reciprocal of three trigonometric ratio. We just swap the numerator and denominator.

\large{csc \theta =  \frac{15}{12}  \longrightarrow  \frac{5}{4} } \\  \large{sec \theta =  \frac{15}{9}  \longrightarrow  \frac{5}{3} }   \\  \large{cot \theta =   \frac{9}{12}  \longrightarrow \frac{3}{4} }

Answer

  • sin = 12/15 —> 4/5
  • cos = 9/15 —> 3/5
  • tan = 12/9 —> 4/3
  • csc = 15/12 —> 5/4
  • sec = 15/9 —> 5/3
  • cot = 9/12 —> 3/4

The first is non-simplifed form while the second that has the arrow pointing is the simplest form.

Let me know if you have any doubts.

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