A single die is rolled twice. the set of 36 equally likely outcomes is {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1),
Maksim231197 [3]
<span>We need to find the rolls whose sum is greater than 10. By looking at the outcomes, we see that (5,6), (6,5), and (6,6) all have a sum greater than 10. Therefore, there are 3 chances to get a sum greater than 10. Since there are 36 chances overall, the probability of rolling greater than 10 are 3/36 = 1/12.</span>
Answer: 2x
^4
+7x−4x
^2
−4
Step-by-step explanation:
2x
^4
−x*3−4x
^2
+10x−4
2x
^4
−3x−4x
^2
+10x−4
2x
^4
+(−3x+10x)−4x
^2
−4
2x
^4
+7x−4x
^2
−4
C the third one
Step by step
Answer:
the characters choices often cause the conflicts
create links to other slides , videos or documents
a presentation that does not have any interaction
Step-by-step explanation:
hope I helped!! ;)
The slope is 1/3 because slope is rise over run so you go up one unit and go right three units.
