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Nataly [62]
3 years ago
14

Rubidium and cesium have similar chemical

Chemistry
1 answer:
yawa3891 [41]3 years ago
8 0
<span>Rubidium and cesium have similar chemical properties because in the ground state the atoms of both elements each have one electron in the outermost shell. The correct option is A. The two elements belong to group one of the periodic table; all elements in this group have only one electron in their outmost shell which they easily give away to other elements during chemical reactions in order to attain octet structure.</span>
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Which of the following aqueous solutions are good buffer systems?
JulsSmile [24]

0.29 M ammonia + 0.38 M ammonium bromide and 0.22 M hypochlorous acid + 0.18 M hydroiodic acids of aqueous solutions are good buffer systems.

<h3>Buffer Systems:</h3>

A solution that resists pH change when acids or bases are added to it is referred to as a buffer system. Either a weak acid and its salt, or a weak base and its salt, make up buffer systems. The ratio of HX/X- does not considerably alter when an acid or a base is introduced to a buffer.

Solutions known as buffers withstand pH changes when an acid or base is added. A weak base (A) and its conjugate weak acid (HA) are both present in buffers. When a reactive system is in equilibrium, adding a strong electrolyte with one common ion will cause the equilibrium to shift, lowering the concentration of the common ion. Buffers differ from one another in terms of pH range and buffer capacity.

Learn more about buffers here:

brainly.com/question/1385846

#SPJ1

5 0
2 years ago
How mant liters at STP are in 0.575 moles of Kr​
gizmo_the_mogwai [7]

Answer:

12.9 L Kr

General Formulas and Concepts:

<u>Chemistry - Gas Laws</u>

  • Using Dimensional Analysis
  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Explanation:

<u>Step 1: Define</u>

0.575 mol Kr

<u>Step 2: Identify Conversions</u>

1 mol= 22.4 L at STP

<u>Step 3: Convert</u>

<u />0.575 \ mol \ Kr(\frac{22.4 \ L \ Kr}{1 \ mol \ Kr} ) = 12.88 L Kr

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

12.88 L Kr ≈ 12.9 L Kr

8 0
3 years ago
Titration Lab Sheet Day 2 (ALTERNATE)
Y_Kistochka [10]
#1 is 95L balanced . #2  is 55^3G balanced.
3 0
3 years ago
Read 2 more answers
If the silver chloride is not dry when its mass is determined, will the calculated percent of silver in the alloy be too high or
sladkih [1.3K]

Too high because there will be extra water weight on the silver chloride therefore making it seem like there is more silver than there actually is

4 0
3 years ago
60 N net force is applied to a 12 KG box. What is the acceleration of the box?
galben [10]

Answer:

The answer is

<h2>5 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and it's net force can be found by using the formula

acceleration =  \frac{force}{mass}  \\

From the question

force = 60 N

mass = 12 kg

So we have

acceleration =  \frac{60}{12}  \\

We have the final answer as

<h3>5 m/s²</h3>

Hope this helps you

8 0
4 years ago
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