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Maru [420]
3 years ago
10

A candy bar has a total mass of 75.0 grams. In a calorimetry experiment, a 1.0-g sample of this candy bar was burned in a calori

meter surrounded by 1000g of water. The temperature of the water in contact with the burning candy bar was measured and found to increase from an initial temperature of 21.2C to a final temperature of 24.3C.
a. Calculate the amount of heat in calories release when the 1.0-g sample burned.
b. Convert the heat in calories to nutritional Calories and then calculate the energy content (fuel value) in Cal/g.
c. Calculate the total caloric content of the candy bar in Calories.
Chemistry
1 answer:
geniusboy [140]3 years ago
6 0
<span>a. 3.1 calories in heat were released by the burning candy bar sample b. The energy value of the sample was 3.1 Cal/g c.The total caloric content of the candy bar is 232.5 Calories, derived by multiplying the total mass of the candy bar by its fuel value per gram</span>
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What reagent would distinguish between Ag+ and Fe3+?
Andreyy89
The reagent which is used is "NaI", that is Sodium iodide.
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Name the two leaders arrested in Amritsar.trace the evenTS that led the Jallianwala bagh massacre.​
san4es73 [151]

Answer:

Explanation:

Answer: The Jallianwala Bagh massacre, also known as the Amritsar massacre, took place on 13 April 1919 when troops of the British Indian Army under the command of Acting Brigadier-General Reginald Dyer fired rifles into a crowd of unarmed Indian civilians who had gathered in Jallianwala Bagh, Amritsar, Punjab. The civilians had assembled for a peaceful protest to condemn the arrest and deportation of two national leaders, Satya Pal and Saifuddin Kitchlew, and to honour the Sikh festival of Baisakhi.

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5 0
3 years ago
An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution?
umka2103 [35]

<u>Answer:</u> The boiling point of solution is 100.53

<u>Explanation:</u>

We are given:

8.00 wt % of CsCl

This means that 8.00 grams of CsCl is present in 100 grams of solution

Mass of solvent = (100 - 8) g = 92 grams

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

Or,

\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Boiling point of pure solution = 100°C

i = Vant hoff factor = 2 (For CsCl)

K_b = molal boiling point elevation constant = 0.51°C/m

m_{solute} = Given mass of solute (CsCl) = 8.00 g

M_{solute} = Molar mass of solute (CsCl) = 168.4  g/mol

W_{solvent} = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

\text{Boiling point of solution}-100=2\times 0.51^oC/m\times \frac{8.00\times 1000}{168.4g/mol\times 92}\\\\\text{Boiling point of solution}=100.53^oC

Hence, the boiling point of solution is 100.53

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