Question

How mant liters at STP are in 0.575 moles of Kr​

Answer 1

Answer:

12.9 L Kr

General Formulas and Concepts:

Chemistry - Gas Laws

• Using Dimensional Analysis
• STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Explanation:

Step 1: Define

0.575 mol Kr

Step 2: Identify Conversions

1 mol= 22.4 L at STP

Step 3: Convert

$0.575 \ mol \ Kr(\frac{22.4 \ L \ Kr}{1 \ mol \ Kr} )$ = 12.88 L Kr

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

12.88 L Kr ≈ 12.9 L Kr