How mant liters at STP are in 0.575 moles of Kr
1 answer:
Answer:
12.9 L Kr
General Formulas and Concepts:
<u>Chemistry - Gas Laws</u>
- Using Dimensional Analysis
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
Explanation:
<u>Step 1: Define</u>
0.575 mol Kr
<u>Step 2: Identify Conversions</u>
1 mol= 22.4 L at STP
<u>Step 3: Convert</u>
<u /> = 12.88 L Kr
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
12.88 L Kr ≈ 12.9 L Kr
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Answer: 306 grams are there in 2.50 moles of potassium chlorate
Explanation
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.
To calculate the number of moles, we use the equation:
given mass of potassium chlorate = ?
Molar mass of potassium chlorate = 122.55 g/mol
Putting in the values we get:
306 grams are there in 2.50 moles of potassium chlorate