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nika2105 [10]
3 years ago
7

Type the correct answer in the box.

Mathematics
1 answer:
Marysya12 [62]3 years ago
8 0

Answer:(-2, 2)

Step-by-step explanation:

7q² - 28 = 0

Add 28 to bothside

7q² - 28 + 28 = 0+ 28

7q² = 28

Divide bothside by 7

7q² / 7 = 28/7

q² = 4

Take the square root of bothside

√q² = ±√4

q = ± 2

q = -2 or q =2

q = (-2, 2)

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Please help need quickly!
MAXImum [283]
Pythagoras
28^2-19^2= 423
Square root of 423 = 20.5669638

Answer = 20.5669638
4 0
3 years ago
(845,230) +-834 -0.4556=
Levart [38]
<span>(845,230) +-834 -0.4556= </span>844395.5444

7 0
3 years ago
Read 2 more answers
5 and 1/7 * 8 <br><br>HELP ME PLZ​
il63 [147K]

Answer:

41 1/7

Step-by-step explanation:

5 1/7 x 8

Convert 5 1/7 to improper fraction

5 1/7 = 36/7

Multiply.

36  x  8

----      --

7   x    1

288/7

Simplify.

41 1/7

---

hope it helps

8 0
3 years ago
A spinner has 6 equally divided sections labeled A, B, C, D, E and F. After spinning the spinner, a number cube is rolled. What
bagirrra123 [75]

Answer: \dfrac{2}{9}

Step-by-step explanation:

Given

The spinner has 6 equal sections A, B, C, D, E, and F

The two events occurred one after the other. So, the probability is the product of the probabilities of each event.

There are two consonants in the given 6 letter

The probability of landing over a consonant  is

P_1=\dfrac{2}{6}

The number greater than 2 in a cube are 3,4,5,6

So, probability corresponding to it

P_2=\dfrac{4}{6}

So, the required probability is

\Rightarrow P=P_1\times P_2\\\Rightarrow P=\dfrac{2}{6}\times \dfrac{4}{6}\\\\\Rightarrow P=\dfrac{8}{36}\\\\\Rightarrow P=\dfrac{2}{9}

8 0
3 years ago
What is the number of positive integers not larger than 210 and not divisible by 2, 3 or 7?
vladimir1956 [14]
Number of +ve integers divisible by 2 less than or equal to 210=a=210/2=105

number of +ve integers divisible by 3 less than or equal to 210=b=210/3=70

number of +ve integers divisible by 7 less than or equal to 210=c=210/7=30

number of +ve integers divisible by 2&3 less than or equal to 210=d=210/6=35

number of +ve integer divisible by 2&7 less than or equal to 210=e=210/14=15

number of +ve integer divisible by 3&7 less than or equal to 210=e=210/21=10

number of +ve integer divisible by 2&7&3 less than or equal to 210=e=210/42=5

<span>number of positive integers not larger than 210 and divisible by 2, 3 or 7=105+70+30-(35+15+10)+5

=150

so numbers not divisible=total-150
                                         =210-150
                                         =</span>60
7 0
3 years ago
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