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Ahat [919]
2 years ago
6

MARKING AS BRAINLIEST!! (Find area of each )

Mathematics
1 answer:
masha68 [24]2 years ago
6 0

Answer:

38 km

Step-by-step explanation:

1. The formula to find the area of a trapezoid is \frac{a+b}{2}h, where a and b are the bases and h is the height.

2. To find the area, all we have to do is plug in these values and simplify!

3. (Solving)

  • \frac{a+b}{2}h
  • \frac{4.3+10.9}{2}*5
  • \frac{15.2}{2}*5
  • \frac{76}{2}
  • 38

Therefore, the area is 38 km.

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How do I solve this problem?
FrozenT [24]
You do

5x2/3

5x2 /3

10/3

3 1/3 is your answer.
4 0
2 years ago
If f(1)=3 and f(n)=-2f(n-1)+ 1, then f(5)=
AlladinOne [14]
Our function is f(n)=-2f(n-1)+1.
We want to find f(5).
Let's substitute 5 for n.
f(5) = -2f(5-1) + 1
f(5) = -2f(4) + 1
We need to know f(4).
f(4) = -2f(4-1) + 1
f(4) = -2f(3) + 1
We need to know f(3).
f(3) = -2f(3-1) + 1
f(3) = -2f(2) + 1
We need to know f(2).
f(2) = -2f(2-1) + 1
f(2) = -2f(1) + 1
We know that f(1) = 3
f(2) = -2(3) + 1
f(2) = -6 + 1
f(2) = -5
Now we can use f(2) = -5 to find f(3)...
f(3) = -2(-5) + 1
f(3) = 10 + 1
f(3) = 11
Now we can use f(3) = 11 to find f(4)...
f(4) = -2(11) + 1
f(4) = -22 + 1
f(4) = -21
Now we can use f(4) = -21 t find f(5)!
f(5) = -2(-21) + 1
f(5) = 42 + 1
f(5) = 43
7 0
2 years ago
Read 2 more answers
The domaln of the following relation R ((6, -2), (1, 2), (-3, -4), (-3, 2)} Is (1 polnt)
castortr0y [4]

Answer:

A. -3,-3,1,6

Step-by-step explanation:

The domain of a relation is the x-coordinates.

7 0
3 years ago
PLS HELPPPP MEEEE I NEED WORK SHOWN TOO
Elanso [62]

The series of operations for each case are listed below:

  1. GCF / GCF / GCF
  2. GCF / Grouping
  3. Quadratic trinomial
  4. GCF / Quadratic trinomial
  5. Difference of squares
  6. Difference of cubes / Quadratic trinomial
  7. Sum of cubes
  8. GCF / Quadratic trinomial
  9. GCF / Difference of squares

<h3>How to applying factor properties to simplify algebraic expressions</h3>

In algebra, factor properties are commonly used to solve certain forms of polynomials in a quick and efficient way and whose effectiveness is sustained on all definitions and theorems known in real algebra. In this problem, we should explain and show what factor properties are used in each case:

Case 1

5 · x · y³ + 10 · x² · y                                             Given

5 · (x · y³ + 2 · x² · y)                                            GCF

5 · x · (y³ + 2 · x · y)                                              GCF

5 · x · y · (y² + 2 · x)                                              GCF

Case 2

6 · z · x + 9 · x + 14 · z + 21                                   Given

3 · x · (z + 3) + 7 · (z + 3)                                       GCF

(3 · x + 7) · (z + 3)                                                  Grouping

Case 3

a² + 2 · a - 63                                                       Given

(a + 9) · (a - 7)                                                       Quadratic trinomial

Case 4

6 · z² + 5 · z - 4                                                     Given

6 · [z² + (5 / 6) · z - 2 / 3]                                      GCF

6 · (z - 1 / 2) · (z + 4 / 3)                                         Quadratic trinomial

Case 5

81 · m² - 25                                                           Given

(9 · m + 5) · (9 · m - 5)                                           Difference of squares

Case 6

8 · x³ - 27                                                               Given

(2 · x - 3) · (4 · x² + 6 · x + 9)                                  Difference of cubes

4 · (2 · x - 3) · [x² + (3 / 2) · x + 9 / 4]                      Quadratic trinomial

Case 7

27 · b³ + 64 · z³                                                      Given

(3 · b + 4 · z) · (9 · b² - 12 · b · z + 16 · z²)               Sum of cubes

Case 8

2 · w³ - 28 · w² + 80 · w                                         Given

2 · w · (w² - 14 · w + 40)                                          GCF

2 · w · (w - 4) · (w - 10)                                             Quadratic trinomial

Case 9

200 · a⁴ - 18 · b⁶                                                     Given

2 · (100 · a⁴ - 9 · b⁶)                                                GCF

2 · (10 · a² + 3 · b³) · (10 · a² - 3 · b³)                       Difference of squares

To learn more on polynomials: brainly.com/question/17822016

#SPJ1

7 0
11 months ago
khanya builders are paid R480 for 8 hours of work,whiles rex builders are paid R660 for 12 hours of work.which company is paid t
kiruha [24]

Answer:

khanya pays higher

Step-by-step explanation:

You have to find the $/hr ratios:

khanya's is 480/8->$60/hr

rex's is 660/12->%55/hr

Khanya pays the higher rate

5 0
2 years ago
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