Answer:
z score Perry 
z score Alice 
Alice had better year in comparison with Perry.
Step-by-step explanation:
Consider the provided information.
One year Perry had the lowest ERA of any male pitcher at his school, with an ERA of 3.02. For the males, the mean ERA was 4.206 and the standard deviation was 0.846.
To find z score use the formula.
Here μ=4.206 and σ=0.846
Alice had the lowest ERA of any female pitcher at the school with an ERA of 3.16. For the females, the mean ERA was 4.519 and the standard deviation was 0.789.
Find the z score
where μ=4.519 and σ=0.789
The Perry had an ERA with a z-score is –1.402. The Alice had an ERA with a z-score is –1.722.
It is clear that the z-score value for Perry is greater than the z-score value for Alice. This indicates that Alice had better year in comparison with Perry.
Answer:
50.29 in^2
Step-by-step explanation:
From the circumference we need to find the radius.
Since C = 2*pi*r, r = C / (2*pi).
Here, with C = 25 1/7 in, r = (25 1/7 in) / [ 2(22/7) ], or r = 4 in
The area of the cake is A = pi*r^2, or (here) A = (22/7)(4 in)^2 = 50.29 in^2
Answer:
124 ft2
Step-by-step explanation:
The yard is a 12ft square so the length and width would both be 12ft. You multiply the length and width of the yard to get the area of the yard so 12x12=144. You have the length and width of the flower bed so 5x4=20. Once you have the area of both you can subtract the area the flower bed takes up of the lawn. 144-20=124 ft2.
12 I got it form Socratic
Answer:
(-8,-10)
Step-by-step explanation:
Rewrite (x+8)2(x+8)² as (x+8)(x+8).
f(x)=3((x+8)(x+8))−10
Expand (x+8) (x+8) using the FOIL Method.
Apply the distributive property.
f(x)=3(x(x+8)+8(x+8))−10
Apply the distributive property.
f(x)=3(x⋅x+x⋅8+8(x+8))−10
Apply the distributive property.
Simplify and combine like terms.
Simplify each term.
Multiply x by x.
f(x)=3(x2+x⋅8+8x+8⋅8)−10
Move 8 to the left of x.
f(x)=3(x2+8⋅x+8x+8⋅8)−10
Multiply 8 by 8.
f(x)=3(x2+8x+8x+64)−10
Add 8x and 8x.
f(x)=3(x2+16x+64)−10
Apply the distributive property.
f(x)=3x2+3(16x)+3⋅64−10
Simplify.
Multiply 16 by 3.
f(x)=3x2+48x+3⋅64−10
Multiply 3 by 64.
f(x)=3x2+48x+192−10
Subtract 10 from 192.
f(x)=3x2+48x+182
The minimum of a quadratic function occurs at x=
If a is positive, the minimum value of the function is f ().
Substitute in the values of aa and b.
x=−
x=-8
Replace the variable x with −8 in the expression.
f(−8)=3(−8)2+48(−8)+182
Y=-10
Therefore, the minimum value is (-8,-10) but if it is asking for just the y-value it would be -10.
