Question

Li...

Answer 1

The price of one vegetarian special lunch is $7 and price of one chicken special lunch is $8.

Step-by-step explanation:

Let,

Price of one vegetarian special lunch = x

Price of one chicken special lunch = y

According to given statement;

21x+40y=467      Eqn 1

28x+36y=484     Eqn 2

Multiplying Eqn 1 by 28

$28(21x+40y=467)\\588x+1120y=13076\ \ \ Eqn\ 3$

Multiplying Eqn 2 by 21

$21(28x+36y=484)\\588x+756y=10164\ \ \ Eqn\ 4$

Subtracting Eqn 4 from Eqn 3

$(588x+1120y)-(588x+756y)=13076-10164\\588x+1120y-588x-756y=2912\\364y=2912$

Dividing both sides by 364

$\frac{364y}{364}=\frac{2912}{364}\\y=8$

Putting y=8 in Eqn 1

$21x+40(8)=467\\21x+320=467\\21x=467-320\\21x=147$

Dividing both sides by 21

$\frac{21x}{21}=\frac{147}{21}\\x=7$

The price of one vegetarian special lunch is $7 and price of one chicken special lunch is $8.

Keywords: linear equation, elimination method

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