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3 years ago

Please help me with these questions

Mathematics

2 answers:

Alina [70]3 years ago

7 0

1 is : d>-9
2 is: k ≥ -18
3 is: g>-1
4 is: n<-40
5 is: w ≤3
That should be correct.

Burka [1]3 years ago

5 0

What that person said

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1) m= -3 (13/3,0)

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2 years ago

The line having an x intercept of 3 and y intercept of 10<br> Write this in Standard form Ax+By=C

Svetlanka [38]

Answer:

The standard form of the line is 10x + 3y = 10

Step-by-step explanation:

First we need to find the slope of the equation, which we can do using the slope equation and the two points given: (3, 0) and (0, 10)

m(slope) = (y2 - y1)/(x2 - x1)

m = (10 - 0)/(0 -3)

m = 10/-3

Now we can write the equation in slope intercept form since we have the slope and the intercept.

y = mx + b

y = -10/3x + 10

Now we can manipulate the equation to get the standard form.

y = -10/3x + 10

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3 years ago

A regular hexagon has sides of 3 feet. What is the area of the hexagon?

frosja888 [35]

Answer:

$13.5\sqrt{3}\:\text{ft}^{2}$

Step-by-step explanation:

Given: The side of a regular hexagon is 3 feet.

To find: Area of the hexagon

Solution:

It is given that the side of a regular hexagon is 3 feet.

We know that the area of a regular hexagon whose side is a units is $\frac{3\sqrt{3} }{2} a^{2}$

Here, the side is 3 feet

So, area of the regular hexagon

$=\frac{3\sqrt{3} }{2} \times3^{2}$

$=\frac{3\sqrt{3} }{2} \times9$

$=\frac{27\sqrt{3} }{2}$

$=13.5\sqrt{3}\:\text{ft}^{2}$

Hence, area of the regular hexagon is $13.5\sqrt{3}\:\text{ft}^{2}$

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3 years ago