All categories

3 years ago

Help in maths question

Mathematics

2 answers:

Rom4ik [11]3 years ago

5 0

Volume of the orange juice in the carton = 10*6*8 = 480 cm^3

when its turned on its side we have the equation 6*20*h = 480 where h = required height
h = 480 / (6*20) = 480 / 120 = 4 cms

answer = 4 cm

zvonat [6]3 years ago

3 0

Answer:

Your answer is 4cm

Step-by-step explanation:

Hope this helped!!!

You might be interested in

Use induction to prove: For every integer n > 1, the number n5 - n is a multiple of 5.

nignag [31]

Answer:

we need to prove : for every integer n>1, the number $n^{5}-n$ is a multiple of 5.

1) check divisibility for n=1, $f(1)=(1)^{5}-1=0$ (divisible)

2) Assume that $f(k)$ is divisible by 5, $f(k)=(k)^{5}-k$

3) Induction,

$f(k+1)=(k+1)^{5}-(k+1)$

$=(k^{5}+5k^{4}+10k^{3}+10k^{2}+5k+1)-k-1$

$=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k$

Now, $f(k+1)-f(k)$

$f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-(k^{5}-k)$

$f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-k^{5}+k$

$f(k+1)-f(k)=5k^{4}+10k^{3}+10k^{2}+5k$

Take out the common factor,

$f(k+1)-f(k)=5(k^{4}+2k^{3}+2k^{2}+k)$ (divisible by 5)

add both the sides by f(k)

$f(k+1)=f(k)+5(k^{4}+2k^{3}+2k^{2}+k)$

We have proved that difference between $f(k+1)$ and $f(k)$ is divisible by 5.

so, our assumption in step 2 is correct.

Since $f(k)$ is divisible by 5, then $f(k+1)$ must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.

Therefore, for every integer n>1, the number $n^{5}-n$ is a multiple of 5.

3 0

2 years ago

1000 POINTS AND BRIANLEST

yanalaym [24]

1. 1456 (1/2 • 13 • 16 • 14)

2. 252 (18 • 14)

3. 1456 (same answer as the first)

7 0

3 years ago

a random sample of 20 high school students was surveyed and asked "how long does it take you to get ready for school in the morn

Ksivusya [100]

Answer:

where are the choices

Step-by-step explanation:

8 0

3 years ago

ALGEBRA 2 PLEASE HELP! QUICKLY!! I AM TERRIBLE AT ALGEBRA AND I HAVE LOADS OF STUFF TO Do TODAY CAN YOU PLEASE HELP ME WITH THIS

Genrish500 [490]

A) the posible roots of the function f(x)=x⁴-3x³-5x²+21x+22 are:
=-1,+1,-2,+2,-11,+11,-22+22.

b)
one zero of the funtion can be: x=-1 ⇒y=0 (-1,0)

c)
other zero of the funtion is: x=-2 ⇒y=0 (-2,0)

d)
if x=0 then y=22 (0,22)

e) In the file is the graph.

4 0

3 years ago

The probability distribution for the random variable x follows. x f(x) 20 0.20 25 0.15 30 0.30 35 0.35 (a) Is this probability d

Damm [24]

Answer:

(a) The probability distribution is valid.

(b) The probability that x = 30 is 0.30.

Step-by-step explanation:

The probability distribution of the random variable X is:

x: 20 | 25 | 30 | 35

f (x): 0.20 | 0.15 | 0.30 | 0.35

(a)

The properties of a probability distribution are:

0 ≤ P (X) ≤ 1
∑ P (X) = 1

All the probability value are more than 0 and less than 1.

Compute the sum of all the probabilities as follows:

$\sum P(X)=0.20+0.15+0.30+0.35=1$

The sum of all probabilities is 1.

Thus, the probability distribution is valid.

(b)

Consider the probability distribution table.

The probability of X = 30 is,

P (X = 30) = 0.30.

Thus, the probability that x = 30 is 0.30.

6 0

3 years ago