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melamori03 [73]
3 years ago
14

Solve the simultaneous equations 5x + 6y = 3 2x - 3y = 12

Mathematics
2 answers:
Serhud [2]3 years ago
7 0

Answer: x =3; y = -2

\left \{ {{5x+6y=3} \atop {2x-3y=12}} \right.\\\\\left \{ {{x=\frac{3-6y}{5} } \atop {2x-3y=12}} \right.\\\\\left \{ {{x=\frac{3-6y}{5} } \atop {2.\frac{3-6y}{5}-3y =12}} \right.\\\\\left \{ {{x=\frac{3-6y}{5} } \atop {6-12y-15y=12.5}} \right.\\\\\left \{ {{x=\frac{3-6y}{5} } \atop {17y=6-60=-54}} \right.\\\\\left \{ {{x=\frac{3-6y}{5} } \atop {y=-54/27}} \right.\\\\\\ \left \{ {{x=\frac{3-6y}{5} } \atop {y=-2}} \right.\\\\\left \{ {{x=3} \atop {y=-2}} \right.

Step-by-step explanation:

vovikov84 [41]3 years ago
4 0

Answer:

x = 3, y = -2.

Step-by-step explanation:

5x + 6y = 3

2x - 3y = 12           Multiply this by 2:

4x - 6y = 24           Now add this to the first equation:

9x = 27

x = 3.

Substitute x = 3 in the second equation:

2(3) - 3y = 12

-3y = 12 - 6 = 6

y = 6 / -3

y = -2.

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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

Sum of 5 and c is greater than -22

↓ <em>Identify</em>

Sum = addition

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Is greater than = inequality

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Add them all together:

5 + c > -22

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3 years ago
What is the factored form of y=x^3+3x^2-x-3 and what the zeros
PSYCHO15rus [73]
   y = x³ + 3x² - x - 3
   0 = x³ + 3x² - x - 3
   0 = x²(x) + x²(3) - 1(x) - 1(3)
   0 = x²(x + 3) - 1(x + 3)
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   0 = (x² + x - x - 1)(x + 3)
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   0 = (x(x + 1) - 1(x + 1))(x + 3)
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Step-by-step explanation:

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