Find the value of x, rounded to the nearest degree

Mathematics

2 answers:

12345 [234]4 years ago

8 0

Hi there! The answer is x = 27.8

To find the length of RS we need to use the sine.
The general formula of the sine is the following
$\sin(x) = \frac{opposite \: side}{hypotenuse}$

When we fill in the formula, we get the following
$\sin(x) = \frac{7}{15} \\ x = \sin {}^{ - 1} ( \frac{7}{15} ) = 27.8$

kondaur [170]4 years ago

6 0

Answer:

x = $27.8^{\circ}$

Step-by-step explanation:

Use Sine rule:

$\sin \theta = \frac{\text{Opposite side}}{\text{Hypotenuse side}}$

As per the statement:

From the given figure:

Opposite side = 7 units

Hypotenuse side = 15 units

Using sine rule:

$\sin x = \frac{7}{15}$

⇒ $x = \sin^{-1}(\frac{7}{15})$

Simplify:

x = 27.8181392847 degree

Therefore, the value of x rounded to the nearest degree is, $27.8^{\circ}$

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If f(x) = ln(2), then limx--->2 (f(2)-f(x))/x-2

Blizzard [7]

Answer:

as written, -2
with denominator parentheses, 0
with f(x)=ln(x) and denominator parentheses, -1/2

Step-by-step explanation:

The problem as stated asks for the limit as x approaches 2 of (0/x) -2.

As written, the limit is (0/2) -2 = -2.

Explanation: f(x) is a constant, so the numerator is 0. The ratio 0/x -2 is defined as -2 everywhere except x=0. So, the value at x=2 is 0/2 -2 = -2.

If you mean (f(2) -f(x))/(x -2), that limit is the limit of 0/(x-2) = 0 as x approaches 2.

Explanation: f(x) is a constant, so the numerator is 0. The ratio 0/(x-2) is zero everywhere except at x=2. The left limit and right limit are both 0 as x approaches 2. Since these limits agree, the limit is said to be 0.

If you mean f(x) = ln(x) and you want the limit of (f(2) -f(x))/(x -2), that value will be -1/2.

Explanation: The value of the ratio is 0/0 at x=2, so we can find the limit using L'Hôpital's rule. Differentiating numerator and denominator, we have ...

lim = (-1/x)/(1)

The value is -1/2 at x=2.