The shape which describe the shape of the sandbox is "A quadrilateral, because angle c and angle x are acute."
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What is Quadrilateral?</h3>
A quadrilateral is a four-sided polygon, having four edges and four corners.
Here, Diagonal = 14 ft.
Length = 12 ft.
Width = 8 ft.
14² = 196, 12² = 144, 8² = 64
8² + 12² ≠ 14²
so it is not a rectangle.
Now, 14² < 12² + 8²
this condition does not occur in rectangle, so it will be a quadrilateral and here sum of square of two adjacent side is greater than the square of third side (Diagonal). So that is an acute angle.
From this situation we can conclude that:
Thus, the shape which describe the shape of the sandbox is "A quadrilateral, because angle c and angle x are acute."
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Answer:
1 1/4
Step-by-step explanation:
Answer:
Alex is right so the problem is solved
Step-by-step explanation:
sin(x/2) = sqrt((1 - cos(x))/2)
cos(x/2) = sqrt((1 + cos(x))/2)
tan(x/2) = sin(x/2)/cos(x/2)
sin(x) = 15/17
so, we can assume the Hypotenuse of the right-angled triangle is 17, the vertical leg is 15.
via Pythagoras we get the 3rd, horizontal side :
17² = 15² + side²
289 = 225 + side²
64 = side²
side = 8
cos(x) = 8/17
sin(x/2) = sqrt((1 - 8/17)/2) = sqrt(9/34) = 3/sqrt(34) =
= 0.514495755...
cos(x/2) = sqrt((1 + 8/17)/2) = sqrt(25/34) = 5/sqrt(34) =
= 0.857492926...
tan(x/2) = 3/sqrt(34) / 5/sqrt(34) = 3/sqrt(34) × sqrt(34)/5 =
= 3/5 = 0.6
