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Natali [406]
3 years ago
11

Tony wants to put $318,000 in his retirement savings account. It earns an interest rate of 7.1% compounded quarterly. He wants t

o determine how much he will have in the account after 5 years, even if he makes no additional contributions or withdrawals to the account
A. $448099.52
B. $347242.34
C. $452115.44
D. $341186.28
which answer correct
Mathematics
1 answer:
Zanzabum3 years ago
8 0

Answer:

C. $452115.44

Step-by-step explanation:

To solve this, we will follow the steps below;

first write down the formula for  compound interest

A= P [ 1 + \frac{r}{n}]^nt

where A is the ending amount

P represent the principal

r represent the interest rate

n represent the number of compounding a year

t represent the time {in years)

from he question above

p= $318 000

r = 0.071

n = 4  since is quarterly

t= 5

we can now proceed to insert the values into the formula

A= P [ 1 + \frac{r}{n}]^nt

  =318 000 [1+\frac{0.071}{4}] ^4(5)

  = $318 000 [1+\frac{0.071}{4}] ^20

   =$318 000 [1+0.01775] ^20

    = $318 000 [1.01775] ^20

     =$318 000× 1.421747

      ≈$452 115.44

He will have $452 115.44 in the account

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Answer:

$2647.18

Step-by-step explanation:

Formula : A[\frac{1+(\frac{r}{n})^{n}-1 }{(\frac{r}{n} )}]

Future value = $43,000

r = rate of interest = 9% = 0.09

t = 3.5 years (compounded quarterly)

n = number of compounding (3.5 × 4) = 14

Now put the values into formula :

43000 = A[\frac{1+(\frac{0.09}{4})^{14}-1 }{(\frac{0.09}{4} )}]

43000=A(\frac{(1+0.0225)^{14}-1}{\frac{0.09}{4}})

43000=A(\frac{(1.0225)^{14}-1}{0.0225})

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We will check each option to find out if the numbers are a multiple of the number. Then we will take the greatest to number to which all of them are a multiple.

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