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2 years ago

PLEASE HELP ME WITH THIS AND EXPLAIN :)

Mathematics

1 answer:

PSYCHO15rus [73]2 years ago

3 0

So first, you need to find the y intercept and slope of the line/function.
then, you just plug it in to y=mx+b form
this one would be:
slope of -5/4
y intercept: 2
so it would be y=-5/4+2

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What is the distance between the points?! round to the nearest tenth i need to show work

Contact [7]

Answer:

8.6

Step-by-step explanation:

To find the distance between two points we use the formula posted below

All we need to do is figure out what the points are on the graph and plug them into the formula... we end up with

the square root of (5-(-2)^2+(2-(-3)^2 and get the answer of 8.602325267

then we round to the nearest tenth and get 8.6

5 0

3 years ago

Solve b to the second power=77

zubka84 [21]

Answer:

$\large\boxed{b=\pm\sqrt{77}}$

Step-by-step explanation:

$b^2=77\iff b=\pm\sqrt{77}\\\\\text{because}\\\\(-\sqrt{77})^2=77\ \text{and} \ (\sqrt{77})^2=77$

3 0

3 years ago

Taxi Driver charges a fixed rate of R to pick up a passenger in addition to Taxi Driver charges a rate of M for each mile driven

IRISSAK [1]

Answer:

t=nm+r

Step-by-step explanation:

Since you are trying to find time, represented by t, you set the equation equal to t. Then you need to add n multiplied by miles, m, to the fixed rate, r.

3 0

2 years ago

Given: △ACM, m∠C=90°, CP ⊥ AM

larisa86 [58]

Answer: The answer is $3\dfrac{4}{7}.$

Step-by-step explanation: Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

$AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.$

Now,

$AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)$

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

$CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)$

Comparing equations (A) and (B), we have

$5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.$

Thus,

$AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.$

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3 years ago

1/3(2x+3)-1/5(x+6)=4

Virty [35]

What are you looking for?

6 0

2 years ago