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nekit [7.7K]
3 years ago
7

Hey peoples im bored and have nun to do

Mathematics
2 answers:
Alexeev081 [22]3 years ago
7 0

Answer:

If you have a sibling play hide and seek or watch tv

Step-by-step explanation:

MaRussiya [10]3 years ago
5 0

Answer:

hey!!

Step-by-step explanation:

how are ya??

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Laura jog around the soccer field that 80m by 120m.how many yards does she goes around the field two times?​
exis [7]

A rectangle has two couples of equal sides, so a soccer fields has two 80-meters sides and two 120-meters sides.

This leads to a perimeter of

120+120+80+80=400 \text{ m}

If you go around it twice, you'll run 800 meters

8 0
3 years ago
HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!! CERTAIN ANSWERS AND I WILL MARK YOU AS BRAINIEST!!!! WISH YOU BEST OF LUCK HOPEFULLY ITS N
AURORKA [14]

Answer:

1)

Minimum is a 4th Degree

2)

Positive; Even

3)

x=-4, -1\text{ Odd Multiplicity}\\x=3\text{ Even Multiplicity}

Step-by-step explanation:

Part 1)

The minimum degree of our function will be 4.

Looking at the graph, we know that the graph crosses the x-axis at -4 and -1. Since it <em>crosses through</em> the x-axis at these two points, these two factors must have an odd multiplicity.

So, it can be anything 1, 3, 5, 7, etc.

However, we will choose the lowest one, 1.

Next, we know that the graph <em>bounces off</em> at 3.

So, it must have an even multiplicity. In other words, 2, 4, 6, 8, etc.

We choose the lowest one, 2.

Therefore, the minimum degree of our function will be 1+1+2 or 4.

Part 2)

The degree of our polynomial is (and will always be) even. Therefore, both ends of the graph will go in the same direction.

Recall the simplest even polynomial, the parent quadratic function. When the leading coefficient is positive, both of the ends go straight up.

This applies to all polynomials with even degrees.

Therefore, since the arms of the graph is going straight up towards positive infinity, the leading coefficient of our graph must be positive.

Part 3)

This is similar to Part 1.

We can see that the graph touches the x-axis at -4, -3, and 1. So, the zeros of the function is: x=-4, -1, 3

We know that it<em> passes through</em> x=-4 \text{ and } x=-1 . So, these two factors must have an odd multiplicity.

However, since the graph <em>bounces off</em> x=3, this factor must have an even multiplicity.

And we're done!

7 0
2 years ago
Sin 3pi divided by 4
KATRIN_1 [288]
Sin 3pi/4 is angle 135 degrees or 45 degrees below 180 degrees. Hence it's opposite side is 1 and adjacent is 1, implying the hypothenus is sqrt(2). Hence

Sin 3pi/4 = 1/sqrt(2). Now multiply by sqrt(2)/sqrt(2) to get:

[1/sqrt(2).] * [sqrt(2)/sqrt(2)] = sqrt2)/2
6 0
3 years ago
How much should a family deposit at the end of every 6 months in order to have $4000 at the end of 3 years? The account pays 5.9
ra1l [238]

We are asked to determine the present value of an annuity that is paid at the end of each period. Therefore, we need to use the formula for present value ordinary, which is:

PV_{ord}=C(\frac{1-(1+i)^{-kn}}{\frac{i}{k}})

Where:

\begin{gathered} C=\text{ payments each period} \\ i=\text{ interest rate} \\ n=\text{ number of periods} \\ k=\text{ number of times the interest is compounded} \end{gathered}

Since the interest is compounded semi-annually this means that it is compounded 2 times a year, therefore, k = 2. Now we need to convert the interest rate into decimal form. To do that we will divide the interest rate by 100:

\frac{5.9}{100}=0.059

Now we substitute the values:

PV_{ord}=4000(\frac{1-(1+0.059)^{-2(3)}}{\frac{0.059}{2}})

Now we solve the operations, we get:

PV_{\text{ord}}=39462.50

Therefore, the present value must be $39462.50

8 0
1 year ago
Divide z by 11. Then, add 8.
yulyashka [42]
This may be the answer,hope it helps

8 0
3 years ago
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