1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elis [28]
3 years ago
6

If two dice are rolled one time, find the probability of getting a sum less than or equal to 4 ​

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
6 0

Answer:

The probability of getting a sum less than or equal to 4 ​is 1/6.

Step-by-step explanation:

When two dices are rolled, the number of outcomes are: 6*6 = 36 which is written in ordered pairs consisting of outcome of both dices.

When two dices are rolled, the number of sample space elements is:

n(S) = 36

Let A be the event that the sum of outcomes is less than or equal to 4:

A = \{(1,1),(1,2),(1,3),(2,1),(2,2),(3,1)\}

That implies

n(A) = 6

The probability of getting sum less than or equal to 4 will be:

P(A) = \frac{n(A)}{n(S)} = \frac{6}{36} = \frac{1}{6}

Hence,

The probability of getting a sum less than or equal to 4 ​is 1/6

You might be interested in
9,000 + 40 + 0.1 + 0.008 I need to put it in standard form. Please help!
Andre45 [30]

Answer:

-12

Step-by-step explanation:

8 0
3 years ago
Look at the picture below to answer the question!! plss
laila [671]

Answer:

x = 15.3°

Step-by-step explanation:

Trig identities:

sin(x)=\dfrac{O}{H} \ \ \ \ \ cos(x)=\dfrac{A}{H} \ \ \ \ \ tan(x)=\dfrac{O}{A}

where

  • x = angle
  • O = side opposite the angle
  • A = side adjacent the angle
  • H = hypotenuse

sin(46)=\dfrac{11}{x}\\\\\implies x=\dfrac{11}{sin(46)}\\\\\implies x=15.3

8 0
2 years ago
Please help !!! I’m stuck
Kruka [31]

Answer:

2/3 ≈ 0.6667

Step-by-step explanation:

apply soh cah toa

sine=opposite/hypo

sine=4/6

sine=2/3

4 0
2 years ago
How many numbers lie between the square of 56 and 57
NARA [144]

Answer:

Given, two numbers 56 and 57 we need to find out the numbers lie between the squares of the given numbers.

Now, we have numbers lying between the square of n and (n + 1) is 2n

⇒ Numbers between squares of 56 and (56 + 1) = 2 × 56 = 112

Hence, 112 numbers lies between the square of the given numbers.

7 0
2 years ago
Read 2 more answers
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
2 years ago
Other questions:
  • What is the answer and how do I solve?
    14·1 answer
  • Create an original rational function that has at least one asymptote (vertical, horizontal, and/or slant) and possibly a removab
    6·1 answer
  • 10/3=?/9 and how do you get the answer
    9·2 answers
  • Here are two steps from the derivation of the quadratic formula,
    11·1 answer
  • A customer will be charged extra if the weight of their suitcase is above 48 pounds.
    9·1 answer
  • The areas of the squares adjacent to two sides of a right triangle are 32 units^2 2 squared and 32 units^2 Find the length, xxx,
    12·1 answer
  • Consider the following sequence: -5, -1, 3,...
    5·1 answer
  • Write 81/45 in simplest form
    6·1 answer
  • A three-dimensional figure is shown. which bet represents that figure?
    10·1 answer
  • pls helppppppppppppppppppppppppppppppppppppppp meeeeeeeeeeeeeeeeeeeeeeeee plsssssssssssssssssssssssssssssss
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!