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pickupchik [31]
3 years ago
9

The square pyramid below represents a tent that Wayne is making. The sides of the tent will be covered in blue fabric, and the b

ase of the tent will be covered in brown fabric, Find the surface area that will be covered in each color of fabric, Enter your answers in the boxes.​

Mathematics
1 answer:
Vladimir79 [104]3 years ago
6 0

Answer:

I am sorry I would love to help but I can't fiqure it out without the side length.

Step-by-step explanation:

btw i know its not your fault i dont  see the width

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PLEASEE I NEED HELP I WILL GIVE BRAINLIST :))) ( btw im dump)
Keith_Richards [23]

Step-by-step explanation:

u know u can download math go and u just take a picture and it will give u the answer

7 0
3 years ago
If the line t is a transversal of lines I and m, NAME THE SPECIAL ANGLE PAIR RELATIONSHIP of the given angle pairs.
Hunter-Best [27]

Answer:

a. <1 and <3

Step-by-step explanation:

8 0
3 years ago
In a field, dry fodder for the cattle is heaped in a
ipn [44]

Answer:

volume of fodder=1/3pie R^2h=\frac{1}{3} *\frac{22}{7} * (3.6)^2 *2.1=28.51m^3

l^2=r^2+h^2

l^2=(2.1)^2+(3.6)^2

l^2=4.441+12.96=17.37

l=\sqrt{17.37}=4.17m

minimum area of polythene to cover fodder=pieRl=\frac{22}{7} *3.6*4.17=47.18m^2

the volume of fodder is 28.51m^3 and minimum area of polythene to cover fodder in the  rainy seasonv47.18m^3

3 0
3 years ago
Help with Algebra 2: 1. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%
Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

1. Given the expression

\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }

Note that

\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}

When dividing \sqrt[7]{x^5} by \sqrt[4]{x^2}, we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

\dfrac{5}{7}-\dfrac{2}{4}=\dfrac{5}{7}-\dfrac{1}{2}=\dfrac{5\cdot 2-1\cdot 7}{14}=\dfrac{3}{14}

and the result is x^{\frac{3}{14}}=\sqrt[14]{x^3}

2. Given equation 3\sqrt[4]{(x-2)^3} -4=20

Add 4:

3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24

Divide by 3:

\sqrt[4]{(x-2)^3} =8

Rewrite the equation as:

(x-2)^{\frac{3}{4}}=8\\ \\(x-2)^{\frac{3}{4}}=2^3

Hence,

\left((x-2)^{\frac{3}{4}}\right)^{\frac{4}{3}}=(2^3)^{\frac{4}{3}}\\ \\x-2=2^{3\cdot \frac{4}{3}}\\ \\x-2=2^4\\ \\x-2=16\\ \\x-2+2=16+2\\ \\x=18

3 0
3 years ago
Please help me asap impor
jeka57 [31]
I’m not sure sorry ☹️
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3 years ago
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