<h2>1)</h2>

This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

<h2>2)</h2>
Well he started off correct to the point of completing the square.

Answer:
d. not a real number
Step-by-step explanation:
it is not a real number because theres a negative under root