Answer:
128
Step-by-step explanation:
Your f(x)=sqrt[x+8]/(x+4)(x-6) is MUCH clearer, but not 100% clear. I will assume that your denominator here is the product of (x+4) and (x-6):
√x+8)
f(x) = ------------------
(x+4)(x-6)
We cannot divide by zero. Thus, x cannot be -4 and cannot be 6.
Thus, the domain is:
(-infinity, -4) or (-4, 6) or (6, infinity).
If <em>f(x)</em> = 7/(1<em> </em>+ <em>x</em>), then
<em>f</em> (2) = 7/3
<em>f '(x)</em> = -7/(<em>x</em> + 1)² ==> <em>f '</em> (2) = -7/9
<em>f ''(x)</em> = 14/(<em>x</em> + 1)³ ==> <em>f ''</em> (2) = 14/27
<em>f '''(x)</em> = -42/(<em>x</em> + 1)⁴ ==> <em>f '''</em> (2) = -14/27
Then the Taylor series of <em>f(x)</em> about <em>a</em> = 2 is
7/3 + 1/1! (-7/9) (<em>x</em> - 2) + 1/2! (14/27) (<em>x</em> - 2)² + 1/3! (-14/27) (<em>x</em> - 2)³
= 7/3 - 7/9 (<em>x</em> - 2) + 7/27 (<em>x</em> - 2)² - 7/81 (<em>x</em> - 2)³
Answer:
πd or 2πr
Step-by-step explanation:
To calculate the circumference of a circle, multiply the diameter of the circle by pi or multiply 2 times the radius times pi.
Hope that helps.
