Assume (a,b) has a minimum element m.
m is in the interval so a < m < b.
a < m
Adding a to both sides,
2a < a + m
Adding m to both sides of the first inequality,
a + m < 2m
So
2a < a+m < 2m
a < (a+m)/2 < m < b
Since the average (a+m)/2 is in the range (a,b) and less than m, that contradicts our assumption that m is the minimum. So we conclude there is no minimum since given any purported minimum we can always compute something smaller in the range.
Answer: 2x-1/4
Step-by-step explanation: Simplify the expression.
Hope this help you out.
Answer:
3.71
Step-by-step explanation:
Add the money.....
-3x - 4y - 2z = 0
x + 3y + 2z = 1
-2x - y = 1
-4x - 4y - 2z = 10
3x + 4y +2z= 0
-x = 10. x = -10
-2(-10) - y = 1
20 - y = 1
-y = -19
y = 19
-10 + 3(19) + 2z = 1
-10 + 57 + 2z = 1
47 + 2z = 1
2z = -46
z= -23
check: 2(-10)+2(19)-23=-5
-20+38-23=-5
-43+38=-5
-5=-5
