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Mathematics

1 answer:

timama [110]2 years ago

6 0

Answer:

128

Step-by-step explanation:

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A cube-shaped aquarium has edges that are 3 feet long and is filled with water that has a density of 62 lbs/ft3 Should the aquar

Sunny_sXe [5.5K]

Given:

There are given the edge of the cube-shaped aquarium has 3 feet.

Explanation:

To find the value, we need to use the volume of the cube formula:

So,

From the formula of volume:

$V=a^3$

Where

a represents the value of edge.

So,

Put the value of edge into the above formula:

Then,

$\begin{gathered} V=a^3 \\ V=3^3 \\ V=27cube\text{ feet} \end{gathered}$

Now,

The water has a density of 62 pounds per cube foot.

According to the question:

If the weight of 1 cubic foot of water is 62 pounds, then the weight of 27 cube feet water is:

$62\times27=1674pound$

Final answer:

Hence, the water weight of the full aquarium is 1674 pounds, and the table only susupports00 pounds. So the table cannot hold the aquarium.

And,

No, the density of water would not change.

6 0

6 months ago

Suppose that w and t vary inversely and that t = 5/12

Svetlanka [38]

Answer:

Option B. t=5/3w ;1/3

Step-by-step explanation:

We are told that $w$ varies Inversely with $t$ thus generally speaking $w$ ∝ $\frac{1}{t}$ since they are inverted, otherwise if they were proportionally varied then $w$ ∝ $t$ . This means that there is a constant value ( $a$ ) for which $w$ is inversely proportional to $t$ and can be mathematically expressed as:

$w=\frac{a}{t}$ Eqn. (1)

Now since we are given the values of $w=4$ and $t=\frac{5}{12}$ , we can plug them in Eqn. (1) and find our constant of proportionality $a$ as follow: