Answer:
Step-by-step explanation:
a matter of stating the ratios as fractions, setting the two fractions equal to each other, cross-multiplying. Ex
3
(2)(9)
x
=
18
3
=
6
x=
3
18
=6
If I have to , I'll include my fractional equation with the arrows. answer is:
x = 6
Answer:
I'm assuming that the variable h is for height, and the W (the total) is for weight, so the answer would be 60 120/263 or 60.456273764259Step-by-step explanation
9514 1404 393
Answer:
f'(x) = (-6x² -14x -23)/(x² +5x +2)²
f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³
Step-by-step explanation:
The applicable derivative formula is ...
d(u/v) = (v·du -u·dv)/v²
__
f'(x) = ((-x² -5x -2)(4x +4) -(2x² +4x -3)(-2x -5))/(-x² -5x -2)²
f'(x) = (-4x³ -24x²-28x -8 +4x³ +18x² +14x -15)/(x² +5x +2)²
f'(x) = (-6x² -14x -23)/(x² +5x +2)²
__
Similarly, the second derivative is the derivative of f'(x).
f''(x) = ((x² +5x +2)²(-12x -14) -(-6x² -14x -23)(2(x² +5x +2)(2x +5)))/(x² +5x +2)⁴
f''(x) = ((x² +5x +2)(-12x -14) +2(6x² +14x +23)(2x +5))/(x² +5x +2)³
f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³
<h3>
Answer: approximately 2076.56001909938
cubic cm</h3>
====================================================
Work Shown:
V1 = volume of cylinder
V2 = volume of cone on top
V3 = V1+V2 = volume of entire 3D solid figure
-----------
V1 = volume of cylinder
V1 = pi*r^2*h
V1 = pi*8.75^2*5.8
V1 = 1395.06348773471 which is approximate
----------
V2 = volume of cone
V2 = (1/3)*pi*r^2*h
V2 = (1/3)*pi*8.75^2*8.5
V2 = 681.49653136466 which is approximate
----------
V3 = V1+V2
V3 = 1395.06348773471+681.49653136466
V3 = 2076.56001909938
Answer is approximate
The units for the volume are in cubic cm.
Answer:
<em>The prediction interval provides an interval estimation for a particular value of y while the confidence interval does it for the expected value of y. </em>
Step-by-step explanation:
<em>A</em><em>. the prediction interval is narrower than the confidence interval.</em>
the prediction interval is always wider than the confidence interval.
<em>B</em><em>. the prediction interval provides an interval estimation for the expected value of y while the confidence interval does it for a particular value of y.</em>
False
<em>C</em><em>. the prediction interval provides an interval estimation for a particular value of y while the confidence interval does it for the expected value of y. </em>
<em>True</em>
<em>D.</em><em> the confidence interval is wider than the prediction interval.</em>
the prediction interval is wider
