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BARSIC [14]
4 years ago
7

data was collected at a tennis court. it showed that being older implies that a player will stay for a shorter length of time. w

hat is likely true
Mathematics
1 answer:
lapo4ka [179]4 years ago
7 0

Answer:

There is a correlation between age and length of stay. There may or may not be causation. Further studies would have to be done to determine this.

Step-by-step explanation:

The answer was checked

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Solve the inequality x > 2 - |2x-1|​
never [62]

Answer:

x 1

Step-by-step explanation:

It can be solved analytically or graphically. Graphically is the fastest way if you know how to handle the two lines. Let's rearrange terms in either case:

x-2>-|2x-1| \rightarrow |2x-1| >2-x

<u>Graphic:</u> Red line is y=2-x, solid blue line is y=|2x-1|, the thin extension is the parent line without the absolute value.

Solving the equation is equivalent to answer "when is the blue line higher than the red one?" Which obviously happens outside the two intercept points. Let's find the first coordinate of both - we don't really care what's the y coordinate of either point.

For the left point, the x coordinate is given by 1-2x = 2-x \rightarrow 2x-1=x-2 \rightarrow x=-1

For the right point, we have

2x-1=2-x \rightarrow 3x=3 \rightarrow x=1

<u>Analytical:</u>

We split the problem in two parts: while the content absolute value is non negative, we have

2x-1 \geq 0\\2x-1 >2-x\\\\x\geq \frac12\\3x > 3 \rightarrow x>1

Which admits as solutions all valeus of x greater than 1 (since both have to be satisfied at once, and values between 1/2 and 1 will not work for the second.

OR, with a negative quantity inside the absolute value, we get

2x-1  2-x\\\\x

which again is satisfied by all values of x less than -1.

Thus the solution is given by x 1

7 0
2 years ago
Help me please!! This is timed and I’m stuck
zhuklara [117]

Let's solve

\\ \sf\longmapsto 2x^2+7x-15=0

\\ \sf\longmapsto x=\dfrac{-7\pm\sqrt{7^2-4(2)(-15)}}{2(2)}

\\ \sf\longmapsto x=\dfrac{-7\pm\sqrt{169}}{4}

\\ \sf\longmapsto x=\dfrac{-7\pm13}{4}

\\ \sf\longmapsto x=\dfrac{-7+13}{4}\:or \:\dfrac{-7-13}{4}

\\ \sf\longmapsto x=\dfrac{6}{4}\:or\:\dfrac{-20}{4}

\\ \sf\longmapsto x=\dfrac{3}{2}\:or -5

Subtract

\\ \sf\longmapsto 3/2-(-5)=3/2+5=13/2

Option B

6 0
3 years ago
Read 2 more answers
Help me! I need this Urgent
lesya692 [45]

Answer:

96.

Step-by-step explanation:

1) if the scale is 1.5:3[ft], then the real lengths are: 12, 16 and 20 [ft];

2) the required area of the real triangle is:

A=0.5*12*16=96 [ft²].

4 0
2 years ago
A+b in terms of a and evaluated these expressions when a = 3​
jeka57 [31]

Answer:

a+b=a

or, 3+b=3 (a=3)

or, b= 3-3

or, b=0

5 0
3 years ago
Solve the system of linear equations using the elimination method: 2x + 2y = 16 -2x +3y = 14
horrorfan [7]

Answer:

Step-by-step explanation:

soulution:

        given,              2x +2x = 16 <em>-</em> <em>2x</em> + 3y = 14

                                 2x <em>+ 2x</em> = <em>-2y </em>+3y = 14 -16

                                       4x = y = -2

                                         y = 4x = -2

                                          y = x =  4/-2

                                         x = y = <u><em>-2 ans</em></u>

4 0
3 years ago
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