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alukav5142 [94]
3 years ago
15

Algebra 1 Can anyone help me with these 2 Math questions?

Mathematics
1 answer:
AnnZ [28]3 years ago
8 0
The answers to the questions

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Suppose that for a certain experiment p​(b​)equals=0.5 and p​(avertical line upper bb​)equals=0.2. find p​(aintersect∩b​).
raketka [301]
P(a | b) = p(a ∩ b)/p(b) . . . . . a definition worth remembering
0.2 = p(a ∩ b)/0.5 . . . . . . . . fill in the given values
0.2*0.5 = 0.1 = p(a ∩ b)

p(a ∩ b) = 0.1
5 0
3 years ago
What is the value of i20+12
Sladkaya [172]

Answer:

Step-by-step explanation:

132

Hope I helepd

4 0
4 years ago
The graph represents the approximate number of bacteria in a population over time. Is the rate of change constant or varying? Ho
alisha [4.7K]

Answer:

Varying

Step-by-step explanation:

The reason why the rate of change is varying is because the dots on the graph do not connect to make a straight line when you draw a line through the dots. When the dots connect via a straight line, it is also known as a proportional relation. A straight line would be a constant change.

8 0
2 years ago
Please help please !!!
Kobotan [32]
<h3>Answer:  12</h3>

========================================================

Explanation:

You can use the AAS (angle angle side) theorem to prove that triangle ABD is congruent to triangle CBD.

From there, we can then say that AD and DC are the same length

AD = DC

3y+6 = 5y-18

3y-5y = -18-6

-2y = -24

y = (-24)/(-2)

y = 12

6 0
3 years ago
Anyone know how to answer this question
mart [117]

9514 1404 393

Answer:

  (x +6)^2 +(y -10)^2 = 225

Step-by-step explanation:

The standard form equation for a circle is ...

  (x -h)^2 + (y -k)^2 = r^2

where the center is (h, k) and the radius is r.

The center of a circle is the midpoint of any diameter. The midpoint between two points is the average of their coordinates.

  ((-15, -2) +(3, 22))/2 = (-15+3, -2+22)/2 = (-6, 10)

The radius can be found using the distance formula, or by simply putting one of the given points in the equation for the circle to see what the constant (r^2) needs to be.

  (x -(-6))^2 +(y -10)^2 = (-15-(-6))^2 +(-2-10)^2

  (x +6)^2 +(y -10)^2 = 81 +144 = 225

The equation of the circle is ...

  (x +6)^2 +(y -10)^2 = 225

5 0
3 years ago
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