Is this statement true or false?

A computer company's stock costs $122 at the start of the day. At the end of the day it costs $93. By what amount did the stock'

Helga [31]

Answer:

the amount the stock changed over the day = $29

Step-by-step explanation:

The stock cost $122 at the start of the day . At the end of the day it cost $93. The amount the stock value changed can be calculated below.

The initial amount of the stock that days was $122 but at the end of the day it changes to $93. This means the stock cost decreases over the day.

Initial cost of stock at the day = $122

Final cost at the end of the day = $93

the amount the stock changes over the day = initial cost of stock at the day - final cost at the end of the day.

the amount the stock changes over the day = 122 - 93

the amount the stock changed over the day = $29

Generally, the stock decreased over the day.

7 0

3 years ago

I Need HelpAsap please I will mark you brainlist

Arada [10]

Answer:

a. 72 inches

b. 21.3 inches

Step-by-step explanation:

12:27

a. 32 inches in height

32/x = 12/27

Set these fractions equal to each other

32= 12

12 times 2.6(repeating decimal) equals 32

So to find the width do 2.666... time 27 and you get 72 inches.

---------------------------------------------------------------------------

b. 48 inches in width

Again set the fractions equal to each other.

x/48 = 12/27

48 divided by 27 equals 1.77777....

To get height, do 1.77777.... times 12 and you get 21.3333333

But since it is to the nearest tenth, you get 21.3 inches

Hope that helps!

5 0

2 years ago

The scatterplot shown includes the (blue) least-squares regression line, whose equation is y = .975 + .005x, where y is calories

ziro4ka [17]

The scatterplot shown includes the (blue) least-squares regression line, whose equation is y = .975 + .005x, where y is calories (in thousands) and x is years after 1960. Choose the correct statement.

Answer: In the given regression equation, the calories are in thousands. Therefore, the slope 0.005 (0.005 x 1000 =5 calories) means the consumption is increasing at a rate of 5 calories per year.

Hence the option a. Consumption is increasing at a rate of 5 calories per year. is correct

4 0

2 years ago

Read 2 more answers

A quality control expert at LIFE batteries wants to test their new batteries. The design engineer claims they have a variance of

iris [78.8K]

Answer:

The probability that the mean battery life would be greater than 533.2 minutes (in a sample of 75 batteries) is $\\ P(z>0.48) = P(x>533.2) = 0.3156$

Step-by-step explanation:

The main thing we have to take into account in this question is that we are about to find the probability of a sample mean. The distribution for sample means follows a normal distribution with mean $\\ \mu$ and standard deviation $\\ \frac{\sigma}{\sqrt{n}}$ . Mathematically

$\\ \overline{x} \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

For values of the sample $\\ n \ge 30$ , no matter the distribution the data come from.

And the variable z follows a standard normal distribution, and, as we can remember, this distribution has a mean = 0 and a standard deviation = 1. Mathematically

$\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$ [1]

That is

$\\ z \sim N(0, 1)$

We have a variance of 3364. That is, a standard deviation of

$\\ \sigma^2 = 3364; \sigma = \sqrt{3364} = 58$

The population mean is

$\\ \mu = 530$

The sample size is $\\ n = 75$

The sample mean is $\\ \overline{x} = 533.2$

With all this information, we can solve the question

The probability that the mean battery life would be greater than 533.2 minutes

Using equation [1]

$\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$\\ z = \frac{533.2 - 530}{\frac{58}{\sqrt{75}}}$

$\\ z = \frac{3.2}{\frac{58}{8.66025}}$

$\\ z = \frac{3.2}{6.69726}$

$\\ z = 0.47780$

With this value of z we can consult a cumulative standard normal table (or use some statistic program) to find the cumulative probability for z (and remember that this variable follows a standard normal distribution).

Most standard normal tables have values for z for only two decimals, so we can round the previous value for z as z = 0.48.

Then

$\\ P(z$

However, in the question we are asked for $\\ P(z>0.48) = P(x>533.2)$ . As well as all normal distributions, the standard normal distribution is symmetrical around the mean, and we have

$\\ P(z>0.48) = 1 - P(z$

Thus

$\\ P(z>0.48) = 1 - 0.68439$

$\\ P(z>0.48) = 0.31561$

Rounding to four decimal places, we have

$\\ P(z>0.48) = 0.3156$

So, the probability that the mean battery life would be greater than 533.2 minutes is (in a sample of 75 batteries) $\\ P(z>0.48) = P(x>533.2) = 0.3156$ .

5 0

3 years ago

Please help again with the following 2 questions

yuradex [85]

Perimeter top one:
5+1+2+3+3+4= 18in

Perimeter bottom one:
6+1+4+3+2+4= 20in

3 0

3 years ago