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taurus [48]
3 years ago
13

What is the completely factored form of d^4 - 81

Mathematics
2 answers:
White raven [17]3 years ago
5 0

Answer:

(d - 3)(d + 3)(d² + 9)

Step-by-step explanation:

d^{4} - 81 ← can be factored as a difference of squares

a² - b² = (a - b)(a + b), thus

d^{4} - 81

= (d²)² - 9²

= (d² - 9)(d² + 9)

Note that d² - 9 is also a difference of square, so

= (d - 3)(d + 3)(d² + 9) ← in factored form

Flauer [41]3 years ago
4 0

Answer:

Step-by-step explanation:

d^4-81

(d^2)^2-(9)^2

Using formula

(d^2+9)(d^2-9)

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