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3 years ago

What is the completely factored form of d^4 - 81

Mathematics

2 answers:

White raven [17]3 years ago

5 0

Answer:

(d - 3)(d + 3)(d² + 9)

Step-by-step explanation:

$d^{4}$ - 81 ← can be factored as a difference of squares

a² - b² = (a - b)(a + b), thus

$d^{4}$ - 81

= (d²)² - 9²

= (d² - 9)(d² + 9)

Note that d² - 9 is also a difference of square, so

= (d - 3)(d + 3)(d² + 9) ← in factored form

Flauer [41]3 years ago

4 0

Answer:

Step-by-step explanation:

d^4-81

(d^2)^2-(9)^2

Using formula

(d^2+9)(d^2-9)

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Answer:

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Step-by-step explanation:

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2 years ago

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

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qwelly [4]

Answer:

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