All categories

3 years ago

What is the completely factored form of d^4 - 81

Mathematics

2 answers:

White raven [17]3 years ago

5 0

Answer:

(d - 3)(d + 3)(d² + 9)

Step-by-step explanation:

$d^{4}$ - 81 ← can be factored as a difference of squares

a² - b² = (a - b)(a + b), thus

$d^{4}$ - 81

= (d²)² - 9²

= (d² - 9)(d² + 9)

Note that d² - 9 is also a difference of square, so

= (d - 3)(d + 3)(d² + 9) ← in factored form

Flauer [41]3 years ago

4 0

Answer:

Step-by-step explanation:

d^4-81

(d^2)^2-(9)^2

Using formula

(d^2+9)(d^2-9)

You might be interested in

Evaluate each of the following values for the f(×)=[×]:

defon

It’s um um.......y......e......a.......h. Yeah

6 0

3 years ago

Wanna see me run to that hill?<br><br> Wanna see me do it again?

kondaur [170]

Answer: uhh no but thanks for the points

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Question 1 of 10

trapecia [35]

Answer:

Step-by-step explanation:

There are 4 queens out of 52 cards in a deck. Therefore, if each card has the same probability of getting chosen, you have a 4/52 = 0.077 chance of drawing a queen because there are (4 favorable outcomes/queens) / (52 total outcomes)

5 0

2 years ago

Please help! 30 points!

Rashid [163]

Answer: $64.2^{\circ}$

Step-by-step explanation:

According to the cosine rule

$\cos C=\dfrac{a^2+b^2-c^2}{2ab}$

Here, $a=83, b=111, c=165,\ C=180^{\circ}-\theta$

Putting values

$\Rightarrow \cos (180^{\circ}-\theta)=\dfrac{83^2+111^2-165^2}{2\times 83\times 111}\\\\\Rightarrow \cos(180^{\circ}-\theta)=\dfrac{6889+12321-27225}{18426}\\\\\Rightarrow \cos(180^{\circ}-\theta)=\dfrac{-8015}{18426}=-0.4349\\\\\Rightarrow 180^{\circ}-\theta=\cos^{-1}(-0.4349)=115.77^{\circ}\\\Rightarrow \theta=64.23\approx 64.2^{\circ}$

So, the ship turns by $64.2^{\circ}$ north of west

8 0

3 years ago

HELP 5TH GRADE MATHJGKG UG

katovenus [111]

Answer:

rectangle, quadrilateral, and square are all right. maybe kite too but I dont think so-

3 0

3 years ago