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Vika [28.1K]
3 years ago
9

A school trip requires students to score at least a total of 335 points on four tests. Each test is worth 100 points. If a stude

nt's scores on the first three tests
were 77, 95, and 82, what score would the student need on the last test to have no less than 335 points ?
O A. 79
OB. 75
O C. 93
O D. 81
Mathematics
2 answers:
trapecia [35]3 years ago
8 0

Answer:

D. 81

Step-by-step explanation:

To get the answer all you need to do is add all of the scores of the first three tests and then subtract that from 335.

HACTEHA [7]3 years ago
6 0

Answer:

D. 81

Step-by-step explanation:

You need to first add 77, 95 and 82 to get 254, Then you do 335 - 254 which is 81.

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5. The regular price of a Space Invader game is $52, but it is on sale. The discount is $13. What is percent discount is this?​
pantera1 [17]

Answer:

Discount Percentage is 25%

Step-by-step explanation:

Original Price: $52

Discount Percentage: -25%

Discount: -$13

Final Price: = $39

4 0
4 years ago
The total bill at a restaurant was $58.25 and included a $12 tip for the server. What was the average spent per person prior to
tatyana61 [14]
Approximately $15.42 each person prior to tip.
3 0
3 years ago
Read 2 more answers
soybean meal is 16% protein; cornmeal is 8% protein. how many pounds of each should be mixed together in order to get 320-lb mix
nlexa [21]

Answer:

120 lb of soybean meal

200 lb of cornmeal

Step-by-step explanation:

S = pounds of soybean meal

C = pounds of cornmeal

S + C = 320  →  C = 320 – S

0.16S + 0.08C = 0.11 × 320 = 35.2

16S + 8C = 3520

16S + 8(320 – S) = 3520

16S + 2560 – 8S = 3520

8S + 2560 = 3520

8S = 960

S = 120

C = 320 – 120 = 200

7 0
3 years ago
A coin is flipped eight times where each flip comes up either heads or tails. How many possible outcomes a) are there in total?
attashe74 [19]

Answer:

There are 256 ways in total.

There are 56 possible outcomes contain exactly three heads.

The possible outcomes contain at least three heads is 219.

The possible outcomes contain the same number of heads and tails are 70.

Step-by-step explanation:

Consider the provided information.

A coin is flipped eight times where each flip comes up either heads or tails.

Part (a) How many possible outcomes are there in total?

Each time we flip a coin it comes up either heads or tail.

Therefore the total number of ways are:

2\times 2\times 2\times 2\times 2\times 2\times 2\times 2=2^8=256

Hence, there are 256 ways in total.

Part (b) contain exactly three heads?

We want exactly 3 heads, therefore,

n=8 and r=3

According to the definition of combination: \binom{n}{r}=\frac{n!}{r!(n-r)!}

\binom{8}{3}=\frac{8!}{3!(5)!}=56

Hence, there are 56 possible outcomes contain exactly three heads.

Part (c) contain at least three heads?

For 3 heads: \binom{8}{3}=\frac{8!}{3!(5)!}=56

For 4 heads: \binom{8}{4}=\frac{8!}{4!(4)!}=70

For 5 heads: \binom{8}{5}=\frac{8!}{5!(3)!}=56

For 6 heads: \binom{8}{6}=\frac{8!}{6!(2)!}=28

For 7 heads: \binom{8}{7}=\frac{8!}{7!(1)!}=8

For 8 heads: \binom{8}{8}=1

Now add them as shown:

56+70+56+28+8+1=219

Hence, the possible outcomes contain at least three heads is 219.

Part (d) contain the same number of heads and tails?

Same number of heads and tails means that the value of r=4.

Therefore,

\binom{8}{4}=\frac{8!}{4!(4)!}=70

Hence, the possible outcomes contain the same number of heads and tails are 70.

6 0
3 years ago
Find the midpoint of points A(10,-7) and B(6, 1) graphically.
sashaice [31]

Answer:

(8,-3)

Step-by-step explanation:

<u>Midpoint Formula: </u> (\frac{x^{1}+x^{2}  }{2}, \frac{y^{1} +y^{2} }{{2} }   )

Plug in your numbers from the coordinates:

(10+6/2, -7+1/2)

(16/2, -6/2)

(8,-3)

4 0
2 years ago
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