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SVETLANKA909090 [29]

3 years ago

9

At 3 p.m., the outside temperature was 4 degrees F. The temperature then fell steadily by 2 degrees F every hour for the next fo

ur hours. What was the temperature at 7 p.m.?

1 answer:

jasenka [17]3 years ago

8 0

-4 degrees Fahrenheit

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Let f(x) = x^2 - 11x - 60.<br> Solve for f(x) using factoring.

Alona [7]

F(x) = X^2 - 11x - 60
Two terms that multiply to -60 and add to -11 so...
F(x) = (X - 15) (x + 4)
Your x-intercepts would be 15 and -4.

4 0

2 years ago

The perimeter of a rectangular garden is 374.

marusya05 [52]

Answer:

The width is 88

Step-by-step explanation:

<u>Perimeter of a rectangle: 2L + 2W</u>

<u />

<u>Step 1: Solve for W</u>

374 = 2(99) + 2W

374 - 198 = 198 + 2W - 198

176 / 2 = 2W / 2

88 = W

Answer: The width is 88

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2 years ago

20 points!!!!! The table represents a linear function

Darya [45]

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3 years ago

An electric bulb is sold in a box measuring 5 cm by 4 cm by 4 cm. If the shopkeeper receives them in a carton measuring 50 cm by

katen-ka-za [31]

Answer:

250

Step-by-step explanation:

Bulb box and carton both are of cuboidal shape.

<u>For bulb </u><u>box</u><u> </u><u>the </u><u>d</u><u>imensions</u><u> </u><u>are:</u>

l = 5 cm, w = 4 cm, h = 4 cm

$V_{Bulb\: box} =lwh$

$\implies V_{Bulb\: box} =5(4)(4)$

$\implies V_{Bulb\: box} =80\: cm^3$

<u>For </u><u>Carton </u><u>the dimensions are</u><u>:</u>

l = 50 cm, w = 20 cm, h = 20 cm

$V_{Carton} =lwh$

$\implies V_{Carton} =50(20)(20)$

$\implies V_{Bulb\: box} =20,000\: cm^3$

To find the number of bulbs packed in the carton, divide the $V_{Carton}$ by $V_{Bulb\: box}$

$Number \:of \:bulbs =\frac{V_{Carton}}{V_{Bulb\: box}}$

$\implies Number \:of \:bulbs =\frac{20,000}{80}$

$\implies Number \:of \:bulbs = 250$

So, 250 bulbs will be packed in one carton.

3 0

2 years ago

Help please For the following function, construct a table.

AysviL [449]

Answer:

See the attachment below.

Step-by-step explanation:

Best Regards!

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2 years ago