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Dafna1 [17]
3 years ago
11

Marina is solving the equation below by using the multiplicative inverse, or the reciprocal. One-fifth (x minus 2) = 20 By which

number should Marina multiply both sides of the equation as the first step in solving it?
Mathematics
2 answers:
miskamm [114]3 years ago
6 0

Answer:

Step-by-step explanation:

Given the equation:

1/5 × (x - 2) = 20

First step to solving the equation is

By multiplying both sides by the value of 5.

That will give,

x - 2 = 100

x = 100 + 2

= 102

kirill [66]3 years ago
5 0

Answer:

The number is 5

Step-by-step explanation:

Using reciprocal method

1/5(x-2)=20

We'll multiply the both sides by the reciprocal of 1/5 which is 5

(1/5)*5(x-2)= 20*5

1(x-2)= 100

X-2 = 100

X= 100+2

X = 102

But note that we multiplied the equation by 5 which is reciprocal of 1/5 as the first step.

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has critical points where both partial derivatives vanish:

∂<em>f</em>/∂<em>x</em> = 2<em>x</em> - 4<em>y</em> = 0   ==>   <em>x</em> = 2<em>y</em>

∂<em>f</em>/∂<em>y</em> = -4<em>x</em> = 0   ==>   <em>x</em> = 0   ==>   <em>y</em> = 0

The origin does not lie in the region <em>R</em>, so we can ignore this point.

Now check the boundaries:

• <em>x</em> = 1   ==>   <em>f</em> (1, <em>y</em>) = 6 - 4<em>y</em>

Then

max{<em>f</em> (1, <em>y</em>) | 0 ≤ <em>y</em> ≤ 2} = 6 when <em>y</em> = 0

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• <em>x</em> = 4   ==>   <em>f</em> (4, <em>y</em>) = 12 - 16<em>y</em>

Then

max{<em>f</em> (4, <em>y</em>) | 0 ≤ <em>y</em> ≤ 2} = 12 when <em>y</em> = 0

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• <em>y</em> = 0   ==>   <em>f</em> (<em>x</em>, 0) = <em>x</em> ² + 5

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min{<em>f</em> (<em>x</em>, 0) | 1 ≤ <em>x</em> ≤ 4} = 6 when <em>x</em> = 1

• <em>y</em> = 2   ==>   <em>f</em> (<em>x</em>, 2) = <em>x</em> ² - 8<em>x</em> + 5 = (<em>x</em> - 4)² - 11

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max{<em>f</em> (<em>x</em>, 2) | 1 ≤ <em>x</em> ≤ 4} = -2 when <em>x</em> = 1

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max{<em>f(x, y)</em> | 1 ≤ <em>x</em> ≤ 4, 0 ≤ <em>y</em> ≤ 2} = 21 at (<em>x</em>, <em>y</em>) = (4, 0)

min{<em>f(x, y)</em> | 1 ≤ <em>x</em> ≤ 4, 0 ≤ <em>y</em> ≤ 2} = -11 at (<em>x</em>, <em>y</em>) = (4, 2)

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