Answer:
14 boys paid for the full year fee and 4 boys paid for the partial year fee
Step-by-step explanation:
Create a system of equations, where x is the number that paid for the $24 fee and y is the number that paid for the $16 fee:
24x + 16y = 400
x = y + 10
Solve by substitution by plugging in y + 10 as x:
24x + 16y = 400
24(y + 10) + 16y = 400
Solve for y:
24y + 240 + 16y = 400
40y + 240 = 400
40y = 160
y = 4
Then, plug in 4 as y to find x:
x = y + 10
x = 4 + 10
x = 14
So, 14 boys paid for the full year fee and 4 boys paid for the partial year fee.
1. 3,-10
2. 10x + y
3. 2x - 3y
Diagram please
Without diagram I cannot tell you the answer
Answers:
14 + 18 ÷ 2 x 18 – 7 = 169
- 14 + 9 * 18 - 7
- 14 + 162 - 7
- 169
60 – 9 x 8 ÷ 8 x 6 = 6
- 60 - 72 / 8 * 6
- 60 + -216/4
- 60 - 54
- 6
15 x 10 + 12 ÷ 3 + 9 = 163
- 150 + 12 / 3 + 9
- 150 + 4 + 9
- 163
(10 ÷ 5)3 + 100 – 9 x 11 = 7
- 2 * 3 + 100 - 9 * 11
- 6 + 100 - 99
- 7
8 x 4 + 9 – 9 + 18 = 50
- 32 + 9 - 9 + 18
- 41 - 9 + 18
- 32 + 18
- 50
3 x 8 x 2 – 42 + 5 = 11
- 24 * 2 - 42 + 5
- 48 - 42 + 5
- 11
<em>i hope this helps, good luck :)</em>
There is no difficulty in this problem until you construct the figures. How can we do it is shown in the attached picture. After drawing PRST, from the point P, we can draw PMKD and later we can complete PMCT as a result. From this picture, we can see that the side of PMCT is also a. Then, the area of this square is
