All categories

3 years ago

Please awnser and make sure it is to I will brainlist

Mathematics

1 answer:

Aleks04 [339]3 years ago

4 0

Answer:

Step-by-step explanation:

Multiple the first number with .1 and you get the second number. Multiple the second number with .1, you get the third number and so forth.

You might be interested in

Y=1/3x what is the slope

Karolina [17]

Answer:

Slope = $\frac{1}{3}$

Step-by-step explanation:

The equation for finding slope is:

$y = mx+b$

In the equation, m is the slope, x is the x-intercept, and b is the y-intercept. The number next to x is ALWAYS the slope.

Your equation:

$y = \frac{1}{3} x$

The number(fraction) next to x is $\frac{1}{3}$ . Therefore, your answer will be $\frac{1}{3}$

3 0

3 years ago

In circle D with m \angle CDE= 76m∠CDE=76 and CD=13CD=13 units find area of sector CDE. Round to the nearest hundredth.

Ksju [112]

Answer:

112.03sq. units

Step-by-step explanation:

The area of a sector = theta/360 * πr²

The area of a sector = 76/360 * 3.14 * 13²

The area of a sector = 76/360 * 530.66

The area of a sector = 40,330.16/360

The area of a sector = 112.03sq. units

This gives the area of the sector

7 0

3 years ago

Use the drop down menus to complete the statements to match the information shown<br> by the graph.

jenyasd209 [6]

Answer:

less than, slope, higher (the rest in not sure)

Step-by-step explanation:

just guessing, could you please show the drop downs??

8 0

3 years ago

Read 2 more answers

Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4

steposvetlana [31]

$f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}$

$\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}$

6 0

4 years ago

Read 2 more answers

I don’t know this one

Taya2010 [7]

74 degrees, because angle 1 and 8 add up to 73 degrees, so to make 180 you subtract 180-73 degrees, which makes 112 degrees for angle 9. Angle 9 and 12 are supplementary so they should both add up to 180. That means that angle 12 must be 68. Angles 12, 7, and 6 must add up to 180, so 38+68=106. 180-106=74. Therefore, angle 6 is 74 degrees

3 0

4 years ago